968 -752 x1001=?
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1) 12 x 19 + (3 x 4) x 24 - (6 x 2) x 33
= 12 x19 + 12 x 24 -12 x 33
= 12 x (19 + 24 - 33)
= 12 x 10
=120
2) 35 x1001-35
=35 x (1001 - 1)
= 35 x 1000
= 35 000
1) 12 x 19 + (3 x 4) x 24 - (6 x 2) x 33
= 12 x19 + 12 x 24 -12 x 33
= 12 x (19 + 24 - 33)
= 12 x 10
=120
2) 35 x1001-35
=35 x (1001 - 1)
= 35 x 1000
= 35 000
752 x 89 - 752 x 9 + 752 x 20
= 752 x ( 89 - 9 + 20 )
= 752 x ( 80 + 20 )
= 752 x 100
= 75200
\(\frac{x-971}{972}+\frac{x-973}{970}+\frac{x-975}{968}+\frac{x-977}{966}=\frac{x-972}{971}+\frac{x-970}{973}+\frac{x-968}{975}+\frac{x-966}{977}\)
\(\Rightarrow\frac{x-971}{972}-1+\frac{x-973}{970}-1+\frac{x-975}{968}-1+\frac{x-977}{966}-1=\frac{x-972}{971}-1+\frac{x-970}{973}-1+\frac{x-968}{975}-1+\frac{x-966}{977}-1\)\(\Rightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}=\frac{x-1943}{971}+\frac{x-1943}{973}+\frac{x-1943}{975}+\frac{x-966}{977}\)
\(\Leftrightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}-\frac{x-1943}{971}-\frac{x-1943}{973}-\frac{x-1943}{975}-\frac{x-966}{977}=0\)
\(\Leftrightarrow\left(x-1943\right).\left(\frac{1}{972}+\frac{1}{970}+\frac{1}{968}+\frac{1}{966}-\frac{1}{971}-\frac{1}{973}+\frac{1}{975}+\frac{1}{977}\right)=0\)
\(\Leftrightarrow\left(x-1943\right)=0\Leftrightarrow x=1943\)
Vậy...
(986-545)+774-254
=441+774-254
=1215 - 254
=961
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