tính nhanh 2018x2019+4036/2019x2020-2
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6 tháng 10 2021
\(C=\dfrac{2}{1\times2}+\dfrac{2}{2\times3}+...+\dfrac{2}{2019\times2020}\)
\(=2\left(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+...+\dfrac{1}{2019\times2020}\right)\)
\(=2\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{2019}-\dfrac{1}{2020}\right)\)
\(=2\left(1-\dfrac{1}{2020}\right)=2.\dfrac{2019}{2020}=\dfrac{2019}{1010}\)
25 tháng 2 2023
a: 43/52>26/52=1/2=60/120
b: 17/68=1/4<1/3=35/105<35/103
c: \(\dfrac{2018\cdot2019-1}{2018\cdot2019}=1-\dfrac{1}{2018\cdot2019}\)
\(\dfrac{2019\cdot2020-1}{2019\cdot2020}=1-\dfrac{1}{2019\cdot2020}\)
2018*2019<2019*2020
=>-1/2018*2019<-1/2019*2020
=>\(\dfrac{2018\cdot2019-1}{2018\cdot2019}< \dfrac{2019\cdot2020-1}{2019\cdot2020}\)
NM
0
LP
0
15 tháng 3 2021
\(\frac{2019}{1\times2}+\frac{2019}{2\times3}+\frac{2019}{3\times4}+...+\frac{2019}{2018\times2019}\)
\(=2019\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{2018\times2019}\right)\)
\(=2019\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2018}-\frac{1}{2019}\right)\)
\(=2019\left(1-\frac{1}{2019}\right)\)
\(=2019\left(\frac{2019}{2019}-\frac{1}{2019}\right)\)
\(=2019\times\frac{2018}{2019}\)\(=\frac{2019\times2018}{2019}=2018\)
Ta có \(\frac{2018\times2019+4036}{2019\times2020-2}\)
\(=\frac{\left(2020-2\right)\times2019}{2019\times2020-2}\)
\(=\frac{2020\times2019-2\times2019+4036}{2019\times2020-2}\)
\(=\frac{2020\times2019-4038+4036}{2019\times2020-2}\)
\(=\frac{2020\times2019-2}{2019\times2020-2}\)
\(=1\)