\(\left(7\times\chi-11\right)^3=2^2\times5^2+200\)
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21 tháng 5 2022
a: \(=\left(\dfrac{17}{10}+\dfrac{70}{10}-\dfrac{87}{10}\right):\left(\dfrac{23}{4}-\dfrac{11}{4}+\dfrac{9}{25}\right)\cdot\left(12,98\cdot0,25\right)+12,5\)
\(=0:\left(3+\dfrac{9}{25}\right)\cdot\left(12,98+0,25\right)+12,5\)
=12,5
b: \(=\dfrac{13}{12}\cdot\dfrac{27}{5}\cdot2\cdot\dfrac{34}{9}\cdot2\cdot\dfrac{2}{17}\)
\(=\dfrac{13}{12}\cdot2\cdot\dfrac{27}{5}\cdot\dfrac{34}{9}\cdot\dfrac{4}{17}\)
\(=\dfrac{13}{6}\cdot\dfrac{27}{5}\cdot\dfrac{8}{9}=\dfrac{8}{6}\cdot3\cdot\dfrac{13}{5}=4\cdot\dfrac{13}{5}=\dfrac{52}{5}\)
14 tháng 10 2020
c
\(=160:\left\{17+\left[9\cdot5-\left(14+2^3\right)\right]\right\}\)
\(=160:\left\{17+\left[45-\left(14+8\right)\right]\right\}\)
\(=160:\left\{17+\left[45-22\right]\right\}\)
\(=160:\left(17+23\right)\)
\(=160:40\)
\(=4\)
d
\(=798+100:\left[16-2\cdot\left(25-22\right)\right]\)
\(=798+100:\left(16-2\cdot3\right)\)
\(=798+100:\left(16-6\right)\)
\(=798+100:10\)
\(=798+10\)
\(=808\)
B
4 tháng 9 2020
Bài làm :
a)\(=-\frac{3}{5}+\frac{28}{5}\times\frac{9}{14}=-\frac{3}{5}+\frac{18}{5}=3\)
b)\(=\frac{55}{126}+\frac{5}{42}+\frac{4}{9}=1\)
c)\(=-\frac{51}{13}-\frac{27}{13}=-6\)
d)\(=\frac{7}{3}-11\frac{1}{4}\times\frac{2}{15}=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\)
e)\(=1\times\frac{8}{3}\times0,25=\frac{2}{3}\)
SS
3
28 tháng 7 2015
\(\left(7x-11\right)^3=2^5.5^2+200\)
\(\left(7x-11\right)^3=1000\)
\(=>7x-11=10\)
\(x=\frac{10+11}{7}=3\)
**** cho mik nhé!
28 tháng 7 2015
\(\left(7x-11\right)^3=2^5\times5^2+200\)
\(\Rightarrow\left(7x-11\right)^3=1000=10^3\)
\(\Rightarrow7x-11=10\)
\(7x=10+11\)
\(7x=21\)
\(x=21\div7\)
\(x=3\)
28 tháng 5 2018
\(\frac{\left(2^3\cdot5\cdot7\right)\cdot\left(5^2\cdot7^3\right)}{\left(2\cdot5\cdot7\right)^2}\)
\(=\frac{2^3\cdot5^3\cdot7^4}{2^2\cdot5^2\cdot7^2}\)
\(=2\cdot5\cdot7^2\)
\(=10\cdot49=490\)
28 tháng 5 2018
\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7\right)^2}\)
\(=\frac{2^3.5^3.7^4}{2^2.5^2.7^2}\)
\(=2.5.7^2\)
\(=\left(2.5\right).7^2\)
\(=10.49\)
\(=490\)
H9
HT.Phong (9A5)
CTVHS
16 tháng 9 2023
\(\dfrac{10}{11}:\left(\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+\dfrac{2}{7\times9}+\dfrac{2}{9\times11}\right)\)
\(=\dfrac{10}{11}:\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right)\)
\(=\dfrac{10}{11}:\left(\dfrac{1}{3}-\dfrac{1}{11}\right)\)
\(=\dfrac{10}{11}:\dfrac{8}{33}\)
\(=\dfrac{10}{11}\times\dfrac{33}{8}\)
\(=5\times\dfrac{3}{4}\)
\(=\dfrac{15}{4}\)
(7.x-11)3=22*52+200
(7.x-11)3=1000 = 103
suy ra: 7x-11=10
7x=10+11
7x=21
x=21:7=3