x + x * 1/3 : 2/9 + x : 2/7 = 252
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y+y x 1/3 : 2/9 + y :2/7 = 252
y x 1 + y x (1/3 x 9/2 ) + y x 7/2 = 252
y x 1/1 + y x 3/2 + y x 7/2 = 252
y x (1/1 + 3/2 + 7/2 ) = 252
y x 6 = 252
y = 252 : 6
y = 42
a)\(\frac{5}{9}\times x-1=\frac{8}{9}\)
\(\frac{5}{9}\times x=\frac{8}{9}+1\)
\(\frac{5}{9}\times x=\frac{17}{9}\)
\(x=\frac{17}{9}:\frac{5}{9}\)
\(x=\frac{17}{5}\)
1: =>x^2+4x-21=0
=>(x+7)(x-3)=0
=>x=3 hoặc x=-7
2: =>(2x-5-4)(2x-5+4)=0
=>(2x-9)(2x-1)=0
=>x=9/2 hoặc x=1/2
3: =>x^3-9x^2+27x-27-x^3+27+9(x^2+2x+1)=15
=>-9x^2+27x+9x^2+18x+9=15
=>18x=15-9-27=-21
=>x=-7/6
6: =>4x^2+4x+1-4x^2-16x-16=9
=>-12x-15=9
=>-12x=24
=>x=-2
7: =>x^2+6x+9-x^2-4x+32=1
=>2x+41=1
=>2x=-40
=>x=-20
Ta có : (x + 2) + (x + 5) + (x + 8) + ...... + (x + 32) = 198
<=> (x + x + x + ...... + x) + (2 + 5 + 8 + ....... + 32) = 198
<=> 11x + 187 = 198
=> 11x = 198 - 187
=> 11x = 11
=> x = 1
\(\Leftrightarrow x+1,5x+3,5x=252\)
<=>6x=252
<=>x=42
ủng hộ nhe
y + y x1/3 : 2/9 + y : 2/7 = 252
y x 1 + y x ( 1/3 x 9/2 ) + y x 7/2 =252
y x1/1 + y x 3/2 + y x 7/2 =252
y x ( 1/1 + 3/2 + 7/2 ) =252
y x ( 2/2 + 3/2 + 7/2 ) =252
y x 6 = 252
y = 252 : 6
y = 42
x+x*\(\frac{1}{2}\):\(\frac{2}{9}\)+x:\(\frac{2}{7}\)=252
x+x*\(\frac{9}{4}\)+x*\(\frac{7}{2}\)=252
x*(1+\(\frac{9}{4}\)+\(\frac{7}{2}\))=252
x*\(\frac{27}{4}\)=252
x=252:\(\frac{27}{4}\)
x=\(\frac{112}{3}\)
Vậy x=\(\frac{112}{3}\)
Học tốt
\(x+x\times\frac{1}{2}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{9}{4}+x\times\frac{7}{2}=252\)
\(x\times\left(1+\frac{9}{4}+\frac{7}{2}\right)=252\)
\(x\times\frac{17}{4}=252\)
\(x=252\div\frac{17}{4}\)
\(x=252\times\frac{4}{17}\)
\(x=\frac{1008}{17}\)
Chắc sai =]]
\(x+x×\frac{1}{3}:\frac{2}{9}+x×\frac{2}{7}=252\)
\(\Rightarrow x+x×\frac{1}{3}×\frac{9}{2}+x×\frac{7}{2}=252\)
\(x\left(1+\frac{1}{3}×\frac{9}{2}+\frac{7}{2}\right)=252\)
\(x×\frac{36}{6}=252\)
\(x×6=252\)
\(x=252:6\)
\(x=43\)
x+x.1/3:2/9+x:2/7=252
x+x.1/3.9/2+x.7/2=252
x(1+1/3+9/2+7/2)=252
x.36/6 =252
=>x =252:6
=>x =42