130-[5.(9-x)+43]=47
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130-[5.(9-x)+43]=47
5.(9-x)+43=130-47
5.(9-x)+43=83
5.(9-x)=83-43
5.(9-x)=40
9-x=40:5
9-x=8
x=9-8
x=1
\(130-\left[5\times\left(9-x\right)+43\right]=47\)
\(\Rightarrow\left[5\times\left(9-x\right)+43\right]=130-47\)
\(\Rightarrow\left[5\times\left(9-x\right)\right]=83\)
\(\Rightarrow\left(9-x\right)=83\div5\)
\(\Rightarrow\left(9-x\right)=\frac{83}{5}\)
\(\Rightarrow x=9-\frac{83}{5}\)
\(\Rightarrow x=-\frac{38}{5}\)
a , 130 - [ 5 . ( 9 - x ) + 43 ] = 47
[ 5 . ( 9 - x ) + 43 ] = 130 - 47
[ 5 . ( 9 - x ) + 43 ] = 83
5 . ( 9 - x ) = 83 - 43
5 . ( 9 - x ) = 40
9 - x = 40 : 5
9 - x = 8
x = 9 - 8
x = 1
b , [ 2 .( 70 - x ) + 23 . 32 ] : 2 = 46
[ 2 . ( 70 - x ) + 8 . 9 ] : 2 = 46
[ 2 . ( 70 - x ) + 72 ] : 2 = 46
[ 2 . ( 70 - x ) + 72 ] = 92
( 70 - x ) + 72 = 92 : 2
( 70- x ) + 72 = 46
( 70 - x ) = 46 - 72
70 - x = - 26
x = 70 - ( - 26 )
x = 70 + 26
x = 96
a.1+3+5+7+...+2x+1=225
[(2x+1-1):2+1]x(2x+1+1):2=225
(x+1)x(2x+2):2=225
(x+1)x(x+1)=225
(x+1)2=225
(x+1)2=152
x+1=15
x=14
_______________
b. 130-[5.(9-x)+43]=47
5.(9-x)+43=83
5.(9-x)=40
9-x=8
x=1
_______________
c.16x<324
24x<220
=>x∈{0;1;2;3;4}
a: =>(x+1)^2=225
=>x+1=15
=>x=14
b: =>[5*(9-x)+43]=130-47=83
=>5(9-x)=40
=>9-x=8
=>x=1
c: =>2^4x<2^20
=>4x<20
=>0<x<5
a) \(128-3\left(x+4\right)=23\)
\(\Rightarrow3\left(x+4\right)=128-23\)
\(\Rightarrow3\left(x+4\right)=105\)
\(\Rightarrow x+4=105:3\)
\(\Rightarrow x+4=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
Vậy x = 31
b) \(\left(6x-3^3\right).5^3=3.5^4\)
\(\Rightarrow6x-27=3.5^4:5^3\)
\(\Rightarrow6x-27=15\)
\(\Rightarrow6x=15+27\)
\(\Rightarrow6x=42\)
\(\Rightarrow x=42:6\)
\(\Rightarrow x=7\)
Vậy x = 7
c) \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Rightarrow119-\left(x-6\right)=2448:24=102\)
\(\Rightarrow x-6=119-102=17\)
\(\Rightarrow x=17+6=23\)
Vậy x = 23
d) \(130-\left[5.\left(9-x\right)+43\right]=47\)
\(\Rightarrow5.\left(9-x\right)+43=130-47=83\)
\(\Rightarrow5.\left(9-x\right)=83-43=40\)
\(\Rightarrow9-x=40:5=8\)
\(\Rightarrow x=9-8=1\)
Vậy x = 1
128 - 3( x+4 ) = 23
=> 3 (x+4) = 128 -23
=> 3(x+4) = 105
=> x+4 = 105 / 3
=> x+4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31
a,x+(-45)=(-62)+17
<=>x=(-62)+17+45
<=>x=0
b,x+29=\(|-43|\)-+(-43)
<=>x=43-43-29
<=>x=-29
c,43+(9-21)=317-(x+317)
<=>31=317-x-317
<=>31=-x
<=>-31=x
d, (15-x)+(x-12)=7-(-5-x)
<=>15-x+x-12=7+5+x
<=>3=12+x
<=>-9=x
e, x-{57-[42+(-23-x)]}=13-{47+[25-(32-x)]}
<=>x-57+42-23-x=13-47-25+32-x
<=>76=-27-x
<=>103=-x
<=>-103=x
f,\(|x|+|-4|=7\)
<=>\(|x|\)+4=7
<=>\(|x|\)=3
<=>x=3 hoặc x=-3