\(\frac{-5}{7}\).\(\frac{6}{19}\)+\(\frac{13}{-7}\).\(\frac{5}{19}\)-\(\frac{15}{7}\)
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VL
3
B
15 tháng 4 2019
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}-\frac{5}{19}-\frac{15}{7}\)
\(=-\frac{5}{7}.\frac{6}{19}+\frac{-13}{7}-\frac{5}{19}-\frac{15}{7}\)
\(=\left(\frac{-5}{7}+\frac{-13}{7}-\frac{15}{7}\right).\left(\frac{6}{19}-\frac{5}{19}\right)\)
\(=\frac{-23}{7}.\frac{1}{19}\)
\(=\frac{-23}{133}\)
15 tháng 4 2019
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}-\frac{5}{19}-\frac{15}{7}\)
\(=\frac{-5}{6}.\frac{6}{19}+\frac{-13}{7}+\frac{-5}{19}+\frac{-15}{7}\)
\(=\frac{-5}{19}+\frac{-13}{7}+\frac{-5}{19}+\frac{-15}{7}\)
\(=\left(\frac{-5}{19}+\frac{-5}{19}\right)+\left(\frac{-13}{7}+\frac{-15}{7}\right)\)
\(=\frac{-10}{19}+\frac{-26}{7}\)
\(=\frac{-564}{133}\)
NN
31 tháng 8 2020
b) \(\frac{12}{19}.\frac{7}{15}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}=\frac{12}{19}.\frac{19}{12}.\frac{-13}{17}.\frac{17}{13}.\frac{7}{15}=1.\left(-1\right).\frac{7}{15}=\frac{-7}{15}\)
31 tháng 8 2020
\(-\frac{5}{7}.\frac{2}{11}+-\frac{5}{7}.\frac{9}{14}+\frac{12}{7}=-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{14}\right)+\frac{12}{7}=-\frac{5}{7}.\frac{127}{154}+\frac{12}{7}=-\frac{635}{1078}+\frac{12}{7}=\frac{1213}{1078}\)
\(\frac{12}{19}.\frac{7}{15}.-\frac{13}{17}.\frac{19}{12}.\frac{17}{13}=\left(\frac{12}{19}.\frac{19}{12}\right).\left(-\frac{13}{17}.\frac{17}{13}\right).\frac{7}{15}=1.-1.\frac{7}{15}=-\frac{7}{15}\)
NH
27 tháng 3 2019
\(a.\frac{108}{119}.\frac{107}{211}+\frac{108}{119}.\frac{104}{211}=\frac{108}{119}.\left(\frac{107}{211}+\frac{104}{211}\right)=\frac{108}{119}.1=108\)
22 tháng 3 2018
ta có;
b=8/3.2/5.3/8.10.19/92
b=16/15.3/8.10.19/92
b=2/5.10.19/92
b=4.19/92
b=19/23
c=-5/7.2/7+-5/7 . 9/14+1/5/7
c=-10/49+(-45)/98+1/5/5
c=131/98
NH
Tính hợp lý
\(\frac{-5}{7}\). \(\frac{6}{19}\)+ \(\frac{13}{-7}\). \(\frac{5}{19}\)- \(\frac{15}{7}\)
1
2 tháng 5 2019
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}.\frac{5}{19}-\frac{15}{7}=\frac{-5}{7}.\frac{6}{19}+\frac{13}{19}.\frac{-5}{7}+\frac{-5}{7}.3\)
\(=\frac{-5}{7}.\left(\frac{6}{19}+\frac{13}{19}+3\right)=\frac{-5}{7}.4=\frac{-20}{7}\)
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}.\frac{5}{19}-\frac{15}{7}\)
\(=\frac{-30}{133}+\frac{65}{-133}-\frac{15}{7}\)
\(=\frac{-30}{133}+\frac{-65}{133}-\frac{15}{7}\)
\(=\frac{-95}{133}-\frac{285}{133}\)
\(=\frac{-380}{133}\)