\(3\frac{1}{3}x+16\frac{3}{4}=-19\frac{1}{4}\)
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7 tháng 8 2019
a) \(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(=1\frac{4}{23}-\frac{4}{23}+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
\(=1+1+0,5=2,5\)
b) \(\frac{3}{7}.19\frac{1}{3}-\frac{3}{7}.33\frac{1}{3}=\frac{3}{7}.\left(19\frac{1}{3}-33\frac{1}{3}\right)\)
\(=\frac{3}{7}.\left(-14\right)=-6\)
c) \(15\frac{1}{4}:\left(-\frac{5}{7}\right)-25\frac{1}{4}:\left(-\frac{5}{7}\right)\)
\(=\left(15\frac{1}{4}-25\frac{1}{4}\right):\left(-\frac{5}{7}\right)\)
\(=\left(-10\right):\left(-\frac{5}{7}\right)\)
\(=14\)
VM
7 tháng 8 2019
a) \(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(=\left(\frac{27}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
\(=1+1+0,5\)
\(=2+0,5\)
\(=2,5.\)
b) \(\frac{3}{7}.19\frac{1}{3}-\frac{3}{7}.33\frac{1}{3}\)
\(=\frac{3}{7}.\left(\frac{58}{3}-\frac{100}{3}\right)\)
\(=\frac{3}{7}.\left(-14\right)\)
\(=-6.\)
c) \(15\frac{1}{4}:\left(-\frac{5}{7}\right)-25\frac{1}{4}:\left(-\frac{5}{7}\right)\)
\(=\left(\frac{61}{4}-\frac{101}{4}\right):\left(-\frac{5}{7}\right)\)
\(=\left(-10\right):\left(-\frac{5}{7}\right)\)
\(=14.\)
Chúc bạn học tốt!
15 tháng 2 2020
\(A=\frac{8\frac{3}{9}\cdot5\frac{1}{4}+3\frac{16}{19}\cdot5\frac{1}{4}}{\left(2\frac{14}{17}-2\frac{1}{34}\right)\cdot34}:\frac{7}{24}\)
\(A=\frac{\left(8\frac{3}{9}+3\frac{16}{19}\right)\cdot5\frac{1}{4}}{\left(2\frac{14}{17}-2\frac{1}{34}\right)\cdot34}\cdot\frac{24}{7}\)
\(A=\frac{\left(\frac{25}{3}+\frac{73}{19}\right)\cdot\frac{21}{4}}{\left(\frac{48}{17}-\frac{69}{34}\right)\cdot34}\cdot\frac{24}{7}\)
\(A=\frac{\frac{694}{57}\cdot\frac{21}{4}}{\frac{27}{34}\cdot34}\cdot\frac{24}{7}=\frac{\left(\frac{2429}{38}\right)}{27}\cdot\frac{24}{7}=\frac{1388}{171}\)
P/S : Số lớn quá
\(3\frac{1}{3}x+16\frac{3}{4}=-19\frac{1}{4}\)
\(\frac{10}{3}x+\frac{67}{4}=\frac{-77}{4}\)
\(\frac{10}{3}x=\frac{-77}{4}-\frac{67}{4}\)
\(\frac{10}{3}x=-36\)
\(x=\left(-36\right):\frac{10}{3}\)
\(x=\frac{-54}{5}\)
\(3\frac{1}{3}x+16\frac{3}{4}=-19\frac{1}{4}\)
\(\Rightarrow\)\(\frac{10}{3}x+\frac{67}{4}=-\frac{77}{4}\)
\(\Rightarrow\)\(\frac{10}{3}x=-\frac{77}{4}-\frac{67}{4}\)
\(\Rightarrow\)\(\frac{10}{3}x=-36\)
\(\Rightarrow\)\(x=-36\times\frac{3}{10}\)
\(\Rightarrow\)\(x=-\frac{54}{5}\)