Question

[kim thị mai trang]

a) \(\frac{x-3}{3}\)- 1= \(\frac{x}{-4}\)

b) \(\frac{5}{8}\)- (\(x-\frac{1}{2}\)) = \(\frac{-3}{4}\)

c)  \(\frac{x}{38}-\frac{1}{19}=\frac{-1}{2}\)

d) \(\frac{x-3}{-15}+\left(x-1\right)=\frac{-5}{3}\)

e)  \(\frac{x-8}{-6}+\frac{1}{2}=x-2\)

g) \(\frac{-6}{8}-\left(-x+\frac{1}{2}\right)=-3\)

h) \(x-\frac{1}{4}=\frac{-2}{14}+\frac{x}{2}\)

k) \(\left(x+3\right)-\left(x+\frac{1}{4}\right)=x\)

Làm hộ mk vs Mơn trước nhé

Nhanh mk tick

Answer 1

[Kiệt Nguyễn]

a) \(\frac{x-3}{3}-1=\frac{x}{-4}\)

\(\Leftrightarrow\frac{x-3}{3}-\frac{3}{3}=\frac{x}{-4}\)

\(\Leftrightarrow\frac{x-6}{3}=\frac{x}{-4}\)

\(\Leftrightarrow-4\left(x-6\right)=3x\)

\(\Leftrightarrow-4x+24=3x\)

\(\Leftrightarrow24=3x+4x\)

\(\Leftrightarrow7x=24\)

\(\Leftrightarrow x=\frac{24}{7}\)

Answer 2

[Kiệt Nguyễn]

b) \(\frac{5}{8}-\left(x-\frac{1}{2}\right)=\frac{-3}{4}\)

\(\Leftrightarrow\frac{5}{8}-x+\frac{1}{2}=\frac{-3}{4}\)

\(\Leftrightarrow\frac{5}{8}+\frac{4}{8}-x=\frac{-3}{4}\)

\(\Leftrightarrow\frac{9}{8}-x=\frac{-3}{4}\)

\(\Leftrightarrow x=\frac{9}{8}+\frac{3}{4}\)

\(\Leftrightarrow x=\frac{15}{8}\)