Tính một cách hợp lí
a) ( - 125 ) . ( + 25 ) . ( - 32 ) . ( - 14 )
b) ( - 2 )3 . ( - 25 ) . ( + 5 ) . ( - 4 )
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a)\(=12\times3+4\times12+12\times3=12\times\left(3+4+3\right)=12\times10=120\)
b)\(=25\times7-25\times2-3\times25-2\times25=25\times\left(7-2-3-2\right)=0\)
a: =46-16+35-5=30+30=60
b: =32-12+34-14+36-16+38-18-10
=20+20+20+20-10
=80-10=70
c: \(=125-125-170+120=-50\)
d: =(-1)+(-1)+...+(-1)
=-50
#\(N\)
`a, 4573 + 46 - 4573 + 35 - 16 - 5`
`= (4573-4573) + (46 - 16)+(35-5)`
`= 0 +30+30 = 60`
`b, 32+34+36+38-10-12-14-16-18`
`= (32-12)+(34-14)+(38-18)+10`
`= 20+20+20+10 = 70`
`c, 125-170+120+(-125)`
`= (125 + -125)-170+120`
`= 0-170+120`
`=-170 + 120 = -50`
`d, 1-2+3-4+...-98+99-100`
Các số hạng có trong biểu thức: \(\left(100-1\right)\div1+1=100\) `(` số hạng `)`
`=> (1-2)+(3-4)+...+(97-98)+(99-100)`
Các cặp mà trong bthuc có là: \(100\div2=50\)
`=> (-1)+(-1)+...(-1)+(-1) = (-50)`
`e,`
*Mình xp sửa đề phải là `1-5 + 7-11+...+997-1001` nhỉ? Vì để như vậy nó lẻ á ._.
`1-5+7-11+...+997-1001`
Các số hạng có trong biểu thức là: \(\left(1001-1\right)\div4+1=251\) `(` số `)`
`-> (1-5)+(7-11)+...+(997-1001)`
Các cặp được ghép ở trong bthuc là: \(251\div2=125,5\)
`-> (-4)+(-4)+...+(-4) = (-4)*125,5 = -502`
a) \(A=27\cdot36+73\cdot99+27\cdot14-49\cdot73\)
\(A=27\cdot\left(36+14\right)+73\cdot\left(99-49\right)\)
\(A=27\cdot50+73\cdot50\)
\(A=50\cdot\left(27+73\right)\)
\(A=50\cdot100\)
\(A=5000\)
b) \(B=\left(4^5\cdot10\cdot5^6+25^5\cdot2^8\right):\left(2^8\cdot5^4+5^7\cdot2^5\right)\)
\(B=\dfrac{\left(2^2\right)^5\cdot2\cdot5\cdot5^6+\left(5^2\right)^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B=\dfrac{2^{11}\cdot5^7+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B-\dfrac{2^8\cdot5^7\cdot\left(2^3\cdot1+5^3\cdot1\right)}{2^5\cdot5^4\cdot\left(2^3\cdot1+5^3\cdot1\right)}\)
\(B=\dfrac{2^8\cdot5^7}{2^5\cdot5^4}\)
\(B=2^3\cdot5^3\)
\(B=10^3\)
\(B=1000\)
`@` `\text {Ans}`
`\downarrow`
`1,`
`a)`
`5 \times 72 \times 10 \times 2`
`= 5 \times 2 \times 10 \times 72`
`= 10 \times 10 \times 72`
`= 100 \times 72`
`= 7200`
`b)`
`40 \times 125`
`= 4 \times 10 \times 25 \times 5`
`= (5 \times 10) \times (4 \times 25)`
`= 50 \times 100`
`= 5000`
`c)`
`4 \times 2021 \times 25`
`= (4 \times 25) \times 2021`
`= 100 \times 2021`
`= 202100`
`d)`
`16 \times 6 \times 25`
`= 4 \times 4 \times 6 \times 25`
`= (4 \times 25) \times 4 \times 6`
`= 100 \times 24`
`= 2400`
`2,`
`a)`
`24 \times 57 + 43 \times 24`
`= 24 \times (57+43)`
`= 24 \times 100`
`= 2400`
`b)`
`12 \times 19 + 80 \times 12 +12`
`= 12 \times (19 + 80 + 1)`
`= 12 \times 100`
`= 1200`
`c)`
`(36 \times 15 \times 169) \div (5 \times 18 \times 13)`
`= 36 \times 15 \times 169 \div 5 \div 18 \div 13`
`= 6 \times 6 \times 3 \times 5 \times 13 \times 13 \div 5 \div 3 \times 6 \div 13`
`= (6 \div 6) \times (3 \div 3) \times (5 \div 5) \times (13 \div 13) \times 6 \times 13`
`= 6 \times 13`
`= 78`
`d)`
`(44 \times 52 \times 60) \div ( 11 \times 13 \times 15)`
`= 44 \times 52 \times 60 \div 11 \div 13 \div 15`
`= 4 \times 11 \times 13 \times 4 \times 15 \times 4 \div 11 \div 13 \div 15`
`= (11 \div 11) \times (13 \div 13) \times (15 \div 15) \times 4 \times 4 \times`
`= 4 \times 4 \times 4`
`= 64`
`3,`
`a)`
`x - 280 \div 35 = 5 \times 54`
`x - 8 = 270`
`x = 270 + 8`
`x = 278`
`b)`
`(x - 280) \div 35 = 54 \div 4`
`(x - 280) \div 35 = 13,5`
`x - 280 = 13,5 \times 35`
`x - 280 = 472,5`
`x = 472,5 + 280`
`x = 752,5`
`c)`
`(x - 128 + 20) \div 192 = 0`
`x - 128 + 20 = 0 \times 192`
`x - 128 + 20 = 0`
`x - 108 = 0`
`x = 0 + 108`
`x = 108`
`d)`
`4 \times (x + 200) = 460 + 85 \times 4`
`4 \times (x+200) = 460 + 340`
`4 \times (x+200) = 800`
`x + 200 = 800 \div 4`
`x + 200 = 200`
`x = 200 - 200`
`x = 0`
`4,`
`a)`
`7/12 - 5/12`
`= (7 - 5)/12`
`= 2/12`
`= 1/6`
`b)`
`8/11 + 19/11`
`= (8+19)/11`
`= 27/11`
`c)`
`3/8 + 5/12`
`= 9/24 + 10/24`
`= 19/24`
`d)`
`3/4 + 7/12`
`= 9/12 + 7/12`
`= 16/12`
`= 4/3`
`5,`
`a)`
`x - 6/7 = 5/2`
`x = 5/2 + 6/7`
`x = 47/14`
`b)`
`12/7 \div x + 2/3 = 7/5`
`12/7 \div x = 7/5 - 2/3`
`12/7 \div x = 11/15`
`x = 12/7 \div 11/15`
`x = 180/77`
`@` `\text {Kaizuu lv uuu}`
a) 5 . 125 . 2 . 41 . 8
= (5 . 8) . (125 . 2) . 41
= 40 . 250 . 41
= 10 000 . 41
= 410 000
b) 25 . 7 . 10 . 4
= (25 . 4 ) . (10 . 7)
= 100 . 70
= 7000
Chúc bạn học tốt!! ^^
a,5.125.2.41.8=(125.8).(2.5).41=1000.10.41=410000
b,25.7.10.4=(25.4).70=100.70=7000
c,8.12.125.2=(8.125).12.2=100.24=2400
d,4.36.25.50=(4.25).(2.50).18=100.100.18=180000
a) ( - 125 ) . (+ 25 ) . ( - 32 ) . ( - 14)
= [( - 125 ) . ( - 32 )] . [ 25 . ( -14 )]
= 4000 . ( - 350 )
= - 1 400 000
b) ( - 2 )3 . ( - 25 ) . ( +5) . ( - 4 )
= ( -8) . ( -25) . 5 . ( - 4 )
= [( - 8 ) . 5 ] . [( - 25 . ( - 4 )]
= ( - 40 ) . 100
= - 4000
\(\left(-125\right).25.\left(-32\right).\left(-14\right)\)
\(=\left(-125\right).25.\left(-8\right).4.\left(-14\right)\)
\(=\left[\left(-125\right).\left(-8\right)\right].\left(25.4\right).\left(-14\right)\)
\(=1000.100.\left(-14\right)\)
\(=-1400000\)