Viết các tích sau dưới sạng lũy thừa
a) 3.2.12.12.3
b)3.5.27.125
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2:
a: n=5^4
=>n=625
b: n^3=125
=>n^3=5^3
=>n=5
c: 11^n=1331
=>11^n=11^3
=>n=3
a) \(a^6\)
b) 4.5.20.20.20=20.20.20.20=\(20^4\)
c) 3.2.12.12.3=6.6.6.6.6.3=\(6^5\).3= \(6^5\),\(6^1\)=\(6^6\)
Phần d mik ko bt lm
a) 3.5.5.3.3.5 = 33.53
b) 2.2.10.10.5 = 2.2.2.5.2.5.5 = 24.53
c) 3.5.27.125 = 3.5.33.53 = 34.54
a,3.5.5.3.3.5=33.53
b,2.2.10.10.5=22.102.5
c,3.5.27.125=3.5.3.3.3.5.5.5=34.54
`3.5 .15.15 = 3.5.3.5.3.5 = 3^3.5^3`
`2.2.5.2.5 = 2^3 . 5^2`
`1000.10 .10 = 10^3 .10^1 . 10^1 = 10^5`
`a.a.a.b.b.b = a^3 . b^3`
`n.n.n + p.p = n^3 . p^2`
a: =15*15*15=15^3
b: =2^3*5^2
c: =10^3*10^2=10^5
d: =a^3*b^3
e: =n^3+p^2
a) \(3\cdot3^4\cdot3^5=3^{10}\)
b) \(7^3:7^2:7=7^{3-2-1}=7^0\)
c) \(\left(x^4\right)^3=x^{12}\)
a, 2.2.10.10.5 = 2.(2.5).10.10 = 2.10.10.10 = 2.10^3
b, 3.5.27.125 = 3.5.3^3.5^3 = 3^4.5^4
c, 2.3.12.12.3 = 2.3.3.2^2.3.2^2.3 = 2^5.3^4
d, 2.3.8.12.24 = 2.3.2^3.3.2^2.2^3.3 = 2^9.3^3
A)2.2.10.10.5=2.(2.5).10.10
=2.10.10.10=21.103
B) 3.5.27.125=3.5.(9.3).(25.5)
=3.5.3.3.3.5.5.5=3.3.3.3.5.5.5.5=34.54
C) 2.3.12.12.3=2.3.(4.3).(4.3).3
=2.3.2.2.3.2.2.3.3=2.2.2.2.2.3.3.3.3=25.34
Đ)2.3.8.12.24=2.3.(2.2).(3.4).(6.2)
=2.3.2.2.3.2.2.3.2.2=27.33
a) \(4^9:4^4\)
\(=4^{9-4}\)
\(=4^5\)
b) \(17^8:17^5\)
\(=17^{8-5}\)
\(=17^3\)
c) \(2^{10}:8^2\)
\(=2^{10}:\left(2^3\right)^2\)
\(=2^{10-6}\)
\(=2^4\)
d) \(18^{10}:3^{10}\)
\(=\left(18:3\right)^{10}\)
\(=6^{10}\)
e) \(27^5:81^3\)
\(=\left(3^3\right)^5:\left(3^4\right)^3\)
\(=3^{15}:3^{12}\)
\(=3^{15-12}\)
\(=3^3\)
f) \(10^6:100\)
\(=10^6:10^2\)
\(=10^{6-2}\)
\(=10^4\)
g) \(5^9:25^3\)
\(=5^9:\left(5^2\right)^3\)
\(=5^9:5^6\)
\(=5^{9-6}\)
\(=5^3\)
h) \(4^{10}:64^3\)
\(=4^{10}:\left(4^3\right)^3\)
\(=4^{10-9}\)
\(=4\)
i) \(2^{25}:32^4:18^4:9^4\)
\(=\left(2^{25}:2^{20}\right):\left(18^4\cdot9^4\right)\)
\(=2^5:9^8:2^4\)
\(=2:9^8\)
\(=\dfrac{2}{9^8}\)
làm hộ mik nhanh lên các bạn