tim x
x/3 =3/x
8/5=-12/x
x/-4=-4/x
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\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
a. \(=\left(\dfrac{12}{15}+\dfrac{3}{15}\right)+\left(\dfrac{4}{3}+\dfrac{5}{3}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\\ =1+2+1=4\)
b. \(x\times\dfrac{3}{4}=\dfrac{1\times3\times6\times5}{6\times5\times5\times3}\\ x\times\dfrac{3}{4}=\dfrac{1}{5}\\ x=\dfrac{1}{5}:\dfrac{3}{4}\\ x=\dfrac{4}{15}\)
ĐKXĐ: x ≠ 3, x ≠ 4, x ≠ 5, x ≠ 6.
Ta có:
Vậy phương trình đã cho có nghiệm là x = 0;x = 9/2.
\(x-\dfrac{3}{4}=2\)
\(x=2+\dfrac{3}{4}\)
\(x=\dfrac{11}{4}\)
`x xx 6/7=5/14`
`=>x=5/14:6/7`
`=>x=5/14xx7/6`
`=>x=35/84`
`=>x=5/12`
Vậy `x=5/12`
__
`x:2/3=4/9`
`=>x=4/9xx2/3`
`=>x=8/27`
Vậy `x=8/27`
__
`x-1/4=3/2`
`=>x=3/2+1/4`
`=>x=6/4+1/4`
`=>x=7/4`
Vậy `x=7/4`
__
`x+4/5=8/9`
`=>x=8/9-4/5`
`=>x=40/45-36/45`
`=>x=4/45`
Vậy `x=4/45`
\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)
\(x\) \(=\dfrac{5}{14}:\dfrac{6}{7}\)
\(x\) \(=\dfrac{5}{12}\)
\(x:\dfrac{2}{3}=\dfrac{4}{9}\)
\(x\) \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)
\(x\) \(=\dfrac{8}{27}\)
\(x-\dfrac{1}{4}=\dfrac{3}{2}\)
\(x\) \(=\dfrac{3}{2}+\dfrac{1}{4}\)
\(x\) \(=\dfrac{7}{4}\)
\(x+\dfrac{4}{5}=\dfrac{8}{9}\)
\(x\) \(=\dfrac{8}{9}-\dfrac{4}{5}\)
\(x\) \(=\dfrac{4}{45}\)
a) \(5^x:\left(5^2\right)^2=625\)
\(5^x:625=625\)
\(5^x=5^8\)=> x = 8
Mấy câu kia tương tự
d) \(\left(x-1\right)^4-\left(x-1\right)^4\cdot\left(x-1\right)^3=0\)
\(\left(x-1\right)^4\cdot\left[1-\left(x-1\right)^3\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\\left(x-1\right)^3=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x-1=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=2\end{cases}}\)
Vậy,..........
\(\frac{x}{3}=\frac{3}{x}\)
\(\Leftrightarrow9=x^2\)
\(\Leftrightarrow x=\sqrt{9}\)
\(\Leftrightarrow x\in\left\{-3;3\right\}\)
\(\frac{8}{5}=\frac{-12}{x}\)
\(\Leftrightarrow8x=-60\)
\(\Leftrightarrow x=\frac{-15}{2}\)
\(\frac{x}{-4}=\frac{-4}{x}\)
\(\Leftrightarrow-x^2=-16\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x=\sqrt{16}\)
\(\Leftrightarrow x\in\left\{-4;4\right\}\)
câu 1 : x = 3
vì 3/3 cũng = 3/3