Tìm x
a, 32x+1 . 11 + 2673
b, \(\frac{45^3.20^4.18^2}{180^5}\)
c. \(\frac{2^{13}+2^5}{2^{10}+2^2}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(=\dfrac{2^{12}\cdot3^{14}}{3^{12}\cdot2^{12}}=3^2=9\)
b: \(=\dfrac{7^3\cdot2\cdot5^3}{5^2\cdot7^2\cdot6}=7\cdot5\cdot\dfrac{1}{3}=\dfrac{35}{3}\)
d: =2^5(2^8+1)/2^2(2^8+1)=2^3=8
c: \(=\dfrac{5^3\cdot3^6\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}=5^2\)
ta có tử =453x204x182=45x45x45x20x20x20x20x18x18
=45x45x45x4x5x4x5x4x5x4x5x18x18
=(45x4x45x4x45x4)x4x5x5x5x5x18x18
=(180x180x180)x4x5x5x5x5x9x2x9x2
=(180x180x180)x(4x5x9x2x2x5x9)x5x5
=(180x180x180x180x180)x25
=1805x25
lại có:180mũ5x25:180mux5=25
H= 45^3.20^4.18^2/ 180^5 = (3^2.5)^3.(2^2.5)^4.(2.3^2)^2/ (2^2.3^2.5)^5 = 3^6.5^3.2^8.5^4.2^2.3^4/ 2^10.3^10.5^5 = 3^10.5^7.2^10/ 2^10.3^10.5^5 = 5^2=25
\(b\)
\(\frac{2^{13+5}}{2^{10+2}}\)=\(\frac{2^{18}}{2^{12}}\)
\(\frac{21^2\cdot14\cdot125}{35^2\cdot6}=\frac{3^2\cdot7^2\cdot2\cdot25\cdot3}{5^2\cdot7^2\cdot2\cdot3}=\frac{3^4\cdot7^2\cdot2\cdot5^2}{5^2\cdot7^2\cdot2\cdot3}=3^3=27..\)
\(\frac{45^3\cdot20^4\cdot18^2}{180^5}=\frac{5^3\cdot9^3\cdot4^4\cdot5^4\cdot2^2\cdot9^2}{2^{10}\cdot3^{10}\cdot5^5}=\frac{5^7\cdot9^5\cdot4^4}{4^5\cdot9^5\cdot5^5}=\frac{1}{4}=0.25\)
\(C=\frac{21^2.14.125}{35^3.6}\)
\(C=\frac{\left(3.7\right)^2.2.7.5^3}{\left(5.7\right)^3.2.3}\)
\(C=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)
\(C=\frac{3^2.7^3.2.5^3}{5^3.7^3.2.3}=3\)
\(D=\frac{45^3.20^4.18^2}{180^5}\)
\(D=\frac{\left(5.3^2\right)^3.\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)
\(D=\frac{5^3.3^6.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)
\(D=\frac{5^7.3^{10}.2^{10}}{2^{10}.3^{10}.5^5}=5^2=25\)
d) Ta có: \(D=\dfrac{21^2\cdot14\cdot125}{35^3\cdot6}\)
\(=\dfrac{7^2\cdot3^2\cdot7\cdot2\cdot5^3}{5^3\cdot7^3\cdot6}\)
\(=\dfrac{3^2\cdot2}{6}=\dfrac{6\cdot3}{6}=3\)
e) Ta có: \(E=\dfrac{45^3\cdot20^4\cdot18^2}{180^5}\)
\(=\dfrac{3^6\cdot5^3\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}\)
\(=\dfrac{3^{10}\cdot5^7\cdot2^{10}}{2^{10}\cdot3^{10}\cdot5^5}=25\)
f) Ta có: \(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}\)
\(=\dfrac{2^5\left(2^8+1\right)}{2^2\left(2^8+1\right)}=\dfrac{2^5}{2^2}=\dfrac{32}{4}=8\)
vip
vip
vip
chúc bạn học ngu