(13x-122):5
tìm x
mong mn giúp e ạ
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\(C=\left(x+1\right)^2+5\ge5\forall x\)
Dấu '=' xảy ra khi x=-1
VIII
1 Have you ever been
2 Did you go
3 went
4 got up
5 have never got
6 got
7 Have you ever seen
D
I
1 B
2 A
3 D
4 A
5 C
\(\left\{{}\begin{matrix}n_{KOH}=0,3.x\left(mol\right)\\n_{Ba\left(OH\right)_2}=0,06\left(mol\right)\end{matrix}\right.\)
\(n_{BaCO_3}=\dfrac{9,85}{197}=0,05\left(mol\right)\)
PTHH: Ba(OH)2 + CO2 --> BaCO3 + H2O
_______0,06--->0,06----->0,06
2KOH + CO2 --> K2CO3 + H2O
0,3x->0,15x---->0,15x
K2CO3 + CO2 + H2O --> 2KHCO3
0,15x->0,15x
BaCO3 + CO2 + H2O --> Ba(HCO3)2
0,01--->0,01
=> 0,06 + 0,3x + 0,01 = 0,1
=> x = 0,1
Trường hợp 1: x - 1 ≥ 0 → x ≥ 1
→ x - 1 = 2x - 5
→ x - 2x = -5 + 1
→ - x = - 4
→ x = 4
Trường hợp 2: x - 1 ≤ 1 → x ≤ 1
→ - ( x - 1) = 2x - 5
→ - x + 1 = 2x - 5
→ -x - 2x = -5 - 1
→ -3x = 6
→ x = 2 (loại)
Vậy, x = 4
Câu 2
\((1) MnO_2 + 4HCl \to MnCl_2 + Cl_2 + 2H_2O\\ (2) Cl_2 + H_2 \xrightarrow{as} 2HCl\\ (3) 3Cl_2 + 2Fe \xrightarrow{t^o} 2FeCl_3\\ (4) 2FeCl_3 + Fe \to 3FeCl_2\\ (5) 2NaOH + Cl_2 \to NaCl + NaClO + H_2O\)
\((1) 4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3\\ (2) 2Fe + 3Cl_2 \xrightarrow{t^o} 2FeCl_3\\ (3) C + O_2 \xrightarrow{t^o} CO_2\\ (4) 2KMnO_4 \xrightarrow{t^o} K_2MnO_4 + MnO_2 + O_2\\ (5) 4P + 5O_2 \xrightarrow{t^o} 2P_2O_5\\ (6) 2KClO_3 \xrightarrow{t^o} 2KCl + 3O_2\\ (7) Fe + H_2SO_4 \to FeSO_4 + H_2\\ (8) Cu + 2H_2SO_4 \to CuSO_4 + SO_2 + 2H_2O\\ (9) 2Fe + 6H_2SO_4 \to Fe_2(SO_4)_3 + 3SO_2 + 6H_2O\\ (10) 2Al + 6H_2SO_4 \to Al_2(SO_4)_3 + 3SO_2 + 6H_2O\)
1.she spends 20 minutes to draw a picture
2.Lan is the most creative in the group
3.No one is smaller than him
4.My pen isn't the same than mine
5.Lan is jealous than her
6.My brother no longer raise pets
-chúc bạn thật thông minh!!!!
(13x-122):5=5
13x-122 = 5 . 5
13x-122 = 25
13x = 25 + 122
13x = 169
x = 169 : 13
x = 13
Vậy x = 13
cảm ơn bn nhé!!