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a) {[( 3^2+1).10-(8:2+6)]:2}+55-(10:5)^3
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2) -3(4 - 7) + 5(-3 + 2)
= -3.4 + 3.7 - 5.3 + 5.2
= -12 + 21 -15 + 10
= 31 - 27
= 4
4) -5(2 - 7) + 4(2 - 5)
= -5.2 + 5.7 + 4.2 - 4.5
= -10 + 35 + 8 - 20
= 38 - 30
= 8
3: \(=20-12-8+12=20-8=12\)
5: \(=-18-42-21-35=-116\)
3: \(=-15+18-12+8=-27+26=-1\)
2: \(=-12+21-15+10=9-5=4\)
1: =-3x5+2x5-7x5+7x4=-8x5+7x4=-40+28=-12
2: =-3x5+3x6-4x3+4x2=-9+8=-1
3: =17(-84-16)=-1700
4: =1975(-115+15)=-197500
5: =-145x13+145x57+57x10-57x145=-1315
1/ \(5\left(-3+2\right)-7\left(5-4\right)\)
\(=5.\left(-3\right)+5.2-7.5-7.\left(-4\right)\)
\(=-15+10-35+28\)
\(=-5-7\)
\(=-12\)
2/ \(3.\left(-5+6\right)-4.\left(3-2\right)\)
\(=3.\left(-5\right)+3.6-4.3-4.\left(-2\right)\)
\(=-15+18-12+8\)
\(=3-4\)
\(=-1\)
3/ \(17.\left(-84\right)+17.\left(-16\right)\)
\(=17.\left(-84-16\right)\)
\(=17.\left(-100\right)\)
\(=-1700\)
4/ \(1975.\left(-115\right)+1975.15\)
\(=1975.\left(-115+15\right)\)
\(=1975.\left(-100\right)\)
\(=-197500\)
5/ \(-145.\left(13-57\right)+57.\left(10-145\right)\)
\(=-145.13-145.\left(-57\right)+57.10+57.\left(-145\right)\)
\(=-145.\left(-57+57\right)-145.13+57.10\)
\(=0-1885+570\)
\(=-1315\)
6/ \(157.17-157.7\)
\(=157.\left(17-7\right)\)
\(=157.10\)
\(=1570\)
7/ \(199.\left(15-17\right)-199.\left(-17+5\right)\)
\(=199.\left(-2\right)-199.\left(-12\right)\)
\(=199.\left(-2\right)+199.12\)
\(=199.\left(-2+12\right)\)
\(=199.10\)
\(=1990\)
8/ \(-39.\left(5-99\right)+99.\left(10-39\right)\)
\(=-39.5-39.\left(-99\right)+99.10+99.\left(-39\right)\)
\(=-39.\left(-99+99\right)-39.5+99.10\)
\(=0-195+990\)
\(=795\)
9/ \(-38.\left(25-4\right)+25.\left(-4+38\right)\)
\(=-38.25-38.\left(-4\right)+25.\left(-4\right)+25.38\)
\(=25.\left(-38+38\right)-4.\left(-38+25\right)\)
\(=0-4.\left(-13\right)\)
\(=52\)
10/ \(\left(-37\right).86+37.76\)
\(=37.\left(-86\right)+37.76\)
\(=37.\left(-86+76\right)\)
\(=37.\left(-10\right)\)
\(=-370\)
\(\dfrac{11}{6}+\dfrac{1}{4}=\dfrac{22}{12}+\dfrac{3}{12}=\dfrac{25}{12}\)
\(\dfrac{2}{5}-\dfrac{3}{8}=\dfrac{16}{40}-\dfrac{15}{40}=\dfrac{1}{40}\)
\(\dfrac{3}{10}-\dfrac{4}{15}=\dfrac{9}{30}-\dfrac{8}{30}=\dfrac{1}{30}\)
\(3+\dfrac{2}{5}=\dfrac{15}{5}+\dfrac{2}{5}=\dfrac{17}{5}\)
\(\dfrac{333}{777}+\dfrac{22}{55}=\dfrac{3}{7}+\dfrac{2}{5}=\dfrac{15}{35}+\dfrac{14}{35}=\dfrac{29}{35}\)
{[( \(3^2\)+ 1 ) .10-(8:2 + 6 ) ] : 2 } + 55 - ( 10 : 5 )\(^3\)
= {[( 9 + 1 ) . 10 - ( 4 + 6 )] : 2 } + 55 - 2\(^3\)
= {[ 10 . 10 - 10 ] : 2 } + 55 - 8
= {[ 100 - 10 ] : 2 } + 47
= { 90 : 2 } + 47
= 45 + 47
= 92