Tìm X biết
( X * 2 +2.7 ) /30 =0.32
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a) \(-\frac{x}{15}=-\frac{60}{x}\Rightarrow-15.\left(-60\right)=x^2\Rightarrow900=x^2\Rightarrow x=\sqrt{900}=30\)
\(x=-\sqrt{900}=-30\)
b) \(-\frac{2}{x}=-\frac{x}{0,32}\Rightarrow-2.\left(-0,32\right)=x^2\Rightarrow\frac{16}{25}=x^2\Rightarrow x=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\)
\(x=-\frac{\sqrt{16}}{\sqrt{25}}=-\frac{4}{5}\)
a) \(\frac{x}{-15}=\frac{-60}{x}\)
=> x.x = (-60) . (-15)
=>x2 = 900
=>x2 = 302
=>x=30
b)\(\frac{-2}{x}=\frac{-x}{0,32}\)
=>x.(-x) =(-2).0,32
=>-(x2) =-0,64
=>-(x2) =-(0,82)
=>x=0,8
219 - 7(x + 1) = 10²
7(x + 1) = 219 - 10²
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
--------------------
(3x - 2⁴) . 7³ = 2.7⁴
(3x - 16).7³ = 2.7⁴
3x - 16 = 2.7⁴:7³
3x - 16 = 2.7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
Lời giải:
$10+2x=4^5:4^3=4^2=16$
$2x=16-10=6$
$x=6:2=3$
---------
$2x-6^2:18=3.2^2$
$2x-2=12$
$2x=14$
$x=14:2=7$
--------------
$70-5(x-3)=3.2^5=96$
$5(x-3)=70-3.2^5=-26$
$x-3=\frac{-26}{5}$
$x=3+\frac{-26}{5}=\frac{-11}{5}$
------------------
$19-7(x+1)=10^2=100$
$7(x+1)=19-100=-81$
$x+1=\frac{-81}{7}$
$x=\frac{-81}{7}-1=\frac{-88}{7}$
------------
$(3x-2^4).7^3=2.7^4$
$3x-16=2.7^4:7^3=2.7=14$
$3x=14+16=30$
$x=30:3=10$
\(a,14-5+x=30\)
\(\Rightarrow9+x=30\Rightarrow x=30-9\)
\(\Rightarrow x=21\)
\(b,45-\left(3+x\right)=14\)
\(\Rightarrow3+x=45-14\)
\(\Rightarrow3+x=31\Rightarrow x=31-3\)
\(\Rightarrow x=28\)
\(c,18+\left(-3+x\right)-\left(44-x\right)=55\)
\(\Rightarrow18-3+x-44+x=55\)
\(\Rightarrow2x-29=55\Rightarrow2x=55+29\)
\(\Rightarrow2x=84\Rightarrow x=84:2\)
\(\Rightarrow x=42\)
\(d,\left(x-45\right).27=0\)
\(\Rightarrow x-45=0\Rightarrow x=45\)
7x+2+2.7x-1=345
=>7x-1(73+2)=345
=>7x-1=345:345=1
=>x-1=0
=>x=1
7^x-1 . 7^x+3 + 2. 7^x-1 = 345
7^x-1 .(7^x+3 + 2) =345
7^x-1. (7^x+3 + 2) = 7^x+3 -2
7^x-1 =(7^x+3 - 2) : (7^x+3 +2)
7^x-1 = 0
=> x-1 = 1
chắc chắn luôn
2,5 x 2,7 < X x 2 < 2,7 x 4,5
6,75 < X x 2 < 12,15
=> x = 4 ; 5 , 6
a.
\(7^{x+2}+2\times7^{x-1}=345\)
\(7^x\times7^2+2\times7^x\div7=345\)
\(7^x\times\left(7^2+\frac{2}{7}\right)=345\)
\(7^x\times\frac{345}{7}=345\)
\(7^x=345\div\frac{345}{7}\)
\(7^x=345\times\frac{7}{345}\)
\(7^x=7\)
\(x=1\)
b.
\(2^{x+2}-2^x=96\)
\(2^x\times\left(2^2-1\right)=96\)
\(2^x\times3=96\)
\(2^x=\frac{96}{3}\)
\(2^x=32\)
\(2^x=2^5\)
\(x=5\)
\(a,7^{x+2}+2.7^{x-1}=345\Rightarrow7^x.49+\frac{2}{7}.7^x=345\Rightarrow7^x\left(49+\frac{2}{7}\right)=345\Rightarrow7^x.\frac{345}{7}=345\Rightarrow7^x=345:\frac{345}{7}=7^1\Rightarrow x=1\)
\(b,2^{x+2}-2^x=96\Rightarrow2^x.4-2^x=96\Rightarrow2^x\left(4-1\right)=96\Rightarrow2^x.3=96\Rightarrow2^x=96:3=32\Rightarrow2^x=2^5\Rightarrow x=5\)
\(a,7^{x+2}+2.7^{x-1}=345=>7^{x-1+3}+2.7^{x-1}=345=>7^{x-1}.7^3+2.7^{x-1}=345\)
\(=>\left(7^3+2\right).7^{x-1}=345=>345.7^{x-1}=345=>7^{x-1}=1=7^0=>x-1=0=>x=1\)
\(b,2^{x+2}-2^x=96=>2^x.2^2-2^x=96=>2^x.\left(4-1\right)=96=>2^x.3=96=>2^x=32=2^5=>x=5\)
\(\frac{\left(x\cdot2\right)+2,7}{30}=0,32\)
=> 2x + 2,7 = 9,6
=> 2x = 6,9
=> x = 3,45
Vậy,..........
Tìm x , biết :
( x × 2 + 2,7 ) / 30 = 0,32
( x × 2 + 2,7 ) : 30 = 0,32
x × 2 + 2,7 = 0,32 × 30
x × 2 + 2,7 = 9,6
x × 2 = 9,6 - 2,7
x × 2 = 6,9
x = 6,9 : 2
x = 3,45
Vậy x = 3,45