\(\left(x+\frac{1}{4}-\frac{1}{3}\right):\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)
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6 tháng 8 2018
\(\left(x+\frac{1}{4}-\frac{1}{3}\right)\div\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)
\(\Leftrightarrow\left(x+\frac{1}{4}-\frac{1}{6}\right)\div\frac{23}{12}=\frac{7}{46}\)
\(\Leftrightarrow x+\frac{1}{4}-\frac{1}{6}=\frac{7}{46}\times\frac{23}{12}\)
\(\Leftrightarrow x+\frac{1}{4}-\frac{1}{6}=\frac{7}{24}\)
\(\Leftrightarrow x+\frac{1}{4}=\frac{7}{24}+\frac{1}{6}\)
\(\Leftrightarrow x+\frac{1}{4}=\frac{11}{24}\)
\(\Leftrightarrow x=\frac{11}{24}-\frac{1}{4}\)
\(\Leftrightarrow x=\frac{5}{24}\)
Học tốt !
11 tháng 7 2016
c.\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\frac{25}{108}.\frac{5751}{25}+\frac{187}{4}}{\frac{100}{21}:-\frac{41}{21}}\)
\(\frac{\frac{213}{4}+\frac{187}{4}}{-\frac{100}{41}}\)
\(\frac{100}{-\frac{100}{41}}=-41\)
11 tháng 7 2016
a. \(\frac{4}{9}:-\frac{1}{7}+6\frac{5}{9}:-\frac{1}{7}\)
\(\left(\frac{4}{9}+6\frac{5}{9}\right):-\frac{1}{7}\)
\(7:-\frac{1}{7}=-49\)
BC
31 tháng 3 2016
(x+-1/12):23/12=7/46
x+(-1/12) =7/46*23/12
x+(-1/12) =7/24
x =7/24-(-1/12)
x =3/8
AI K mik , mik K lại cho
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):\) \(\frac{23}{12}\) \(=\frac{7}{46}\)
\(x+\frac{1}{4}-\frac{1}{3}\) \(=\frac{7}{45}\times\frac{23}{12}\)
\(x+\frac{1}{4}-\frac{1}{3}\) \(=\frac{161}{540}\)
\(x+\frac{1}{4}\) \(=\frac{161}{450}+\frac{1}{3}\)
\(x+\frac{1}{4}\) \(=\frac{311}{450}\)
\(x\) \(=\frac{311}{450}-\frac{1}{4}\)
\(x\) \(=\frac{397}{900}\)
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)
\(\Leftrightarrow\left(x-\frac{1}{12}\right):\frac{23}{12}=\frac{7}{46}\)
\(\Leftrightarrow x-\frac{1}{12}=\frac{7}{24}\)
\(\Leftrightarrow x=\frac{3}{8}\)