Tính nhanh 3.18.12+18.2.24-4.32.9 ?
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\(3\cdot18\cdot12+4\cdot82\cdot9\)
\(=36\cdot18+36\cdot82\)
\(=36\cdot\left(18+82\right)\)
\(=36\cdot100\)
\(=3600\)
3.18.12+4.82.9
= 3.12.18+4.9.82
= 36.18+36.82
= 36.(18+82)
=36.100
3600
d)\(\left(\dfrac{1}{3}\right)^{50}.\left(-9\right)^{25}-\dfrac{2}{3}:4=\dfrac{1}{3^{50}}.\left(-3^{50}\right)-\dfrac{1}{6}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
e) \(=\left(4.\dfrac{3}{4}-\dfrac{1}{2}\right).\dfrac{6}{5}-17=\left(3-\dfrac{1}{2}\right).\dfrac{6}{5}-17=\dfrac{5}{2}.\dfrac{6}{5}-17=3-17=-14\)
\(=\dfrac{99\cdot44.44\cdot2\cdot13.20\cdot4}{3.3\cdot88.88\cdot2\cdot6.6\cdot8\cdot5}=\dfrac{99}{3.3}\cdot\dfrac{1}{2}\cdot2\cdot\dfrac{1}{2}\cdot\dfrac{1}{5}=30\cdot\dfrac{1}{5}=6\)
\(=\dfrac{3}{4}.\dfrac{-8}{5}+\dfrac{1}{4}=-\dfrac{6}{5}+\dfrac{1}{4}=-\dfrac{19}{20}\)
\(\left(\dfrac{1}{2020}-\dfrac{2018}{2019}\right):\dfrac{2}{9}-\left(\dfrac{-2019}{2020}+\dfrac{1}{2019}\right):\dfrac{2}{3}=\)
\(\left(\dfrac{1}{2020}-\dfrac{2018}{2019}\right)\cdot\dfrac{3}{2}-\left(\dfrac{-2019}{2020}+\dfrac{1}{2019}\right)\cdot\dfrac{3}{2}=\)
\(\left[\left(\dfrac{1}{2020}-\dfrac{2018}{2019}\right)-\left(\dfrac{-2019}{2020}+\dfrac{1}{2019}\right)\right]\cdot\dfrac{3}{2}=\)
\(\left[\dfrac{1}{2020}-\dfrac{2018}{2019}-\dfrac{2019}{2020}-\dfrac{1}{2019}\right]\cdot\dfrac{3}{2}=\)
\(0\)
\(\left(\dfrac{4}{13}-\dfrac{13}{5}\right):\dfrac{4}{5}+\left(\dfrac{9}{13}+\dfrac{3}{5}\right):\dfrac{4}{5}\)
\(=\left(\dfrac{4}{13}-\dfrac{13}{5}\right)\cdot\dfrac{5}{4}+\left(\dfrac{9}{13}+\dfrac{3}{5}\right)\cdot\dfrac{5}{4}\)
\(=\left[\dfrac{4}{13}-\dfrac{13}{5}+\dfrac{9}{13}+\dfrac{3}{5}\right]\cdot\dfrac{5}{4}\)
\(=\dfrac{-5}{4}\)
(-23)+13+(-17)+57
=[(-23)+13]+[(-17)+57]
=(-10)+40
=30
hok tốt
Bạn ưi..
Tính cách nhanh hay tính bth cx ra kq là 30 mak
Chắc do bạn tính sai đó
Bạn kiểm tra lại xem
^^
=3.18.12+18.2.24-4.32.9
=36.18+36.24-36.32
=36(18+24-32)
=36.10=360
\(3.18.12+18.2.24-4.32.9\)
\(=36.18+36.24-36.32\)
\(=36\left(18+24-32\right)\)
\(=36.10\)
\(=360\)