Question

[Phạm Mai Anh]

1) Tính giá trị biểu thức

a) A= \(\dfrac{2}{\sqrt{3}+1}\) + \(\dfrac{1}{\sqrt{3}-2}\) +\(\dfrac{6}{\sqrt{3}+3}\)

b) B= \(\dfrac{-7}{\sqrt{6}+\sqrt{5}}\) + \(\dfrac{\sqrt{2}}{\sqrt{6}}\) - \(\dfrac{7}{2+\sqrt{5}}\)

c) C= \(\dfrac{5+\sqrt{5}}{5-\sqrt{5}}\) + \(\dfrac{5-\sqrt{5}}{5+\sqrt{5}}\)

d) D= \(\left(\dfrac{2}{\sqrt{5}-\sqrt{3}}-\dfrac{2}{\sqrt{5}+\sqrt{3}}-4\right):\dfrac{2+\sqrt{3}}{\sqrt{3}-2}\)

2) Tính giá trị biểu thức

a) A= \(\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}\)

b) B= \(\sqrt{17-12\sqrt{2}}-\sqrt{9+4\sqrt{2}}\)

c) C= \(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)

d) D= \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)

Các bạn giúp mk với nhé! Mai mk phải nộp r

Answer 1

[Phùng Khánh Linh]

Bài 1 bạn nhóm , trục như thường nhé :D

Bài 2. \(a.A=\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}=\sqrt{3+2\sqrt{3}.\sqrt{2}+2}-\sqrt{3-2\sqrt{3}.\sqrt{2}+2}=\sqrt{3}+\sqrt{2}-\sqrt{3}+\sqrt{2}=2\sqrt{2}\)

\(b.B=\sqrt{17-12\sqrt{2}}-\sqrt{9+4\sqrt{2}}=\sqrt{9-2.2\sqrt{2}.3+8}-\sqrt{8+2.2\sqrt{2}+1}=3-2\sqrt{2}-2\sqrt{2}-1=2-4\sqrt{2}\)

\(c.C=\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}=\sqrt{13+30\sqrt{2+\sqrt{8+2.2.\sqrt{2}+1}}}=\sqrt{13+30\sqrt{2+2\sqrt{2}+1}}=\sqrt{43+30\sqrt{2}}=\sqrt{25+2.3\sqrt{2}.5+18}=5+3\sqrt{2}\)

\(d.D=\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)

\(D^2=24-2\sqrt{\left(12-3\sqrt{7}\right)\left(12+3\sqrt{7}\right)}=24-2\sqrt{81}=24-18=6\)

\(D=-\sqrt{6}\left(do:D< 0\right)\)

Answer 2

[Phạm Mai Anh]

cảm ơn bn nhé!!!