Question

[Hoshimiya Ichigo]

Tính nhanh ( Nếu có thể )

a ) \(\frac{13}{15}+\frac{4}{7}-\frac{101}{105}\)

b ) \(\frac{2}{5}+\frac{3}{5}\cdot\frac{4}{5}\)

c ) \(\frac{254\cdot399-145}{254+399\cdot253}\)

d ) \(\frac{5932+6001\cdot5931}{5932\cdot6001-69}\)

e ) \(\frac{1}{5}:\frac{2}{7}\)

GẤP , CỰC KÌ GẤP ..... BẠN NÀO TRÌNH BÀY ĐẦY ĐỦ MÌNH TICK .... T_T

Answer 1

[Nguyễn Thị Quỳnh Tiên]

a )\(\frac{13}{15}+\frac{4}{7}-\frac{101}{105}\)

\(=\frac{91}{105}+\frac{60}{105}-\frac{101}{105}\)

\(=\frac{50}{105}\)

\(=\frac{10}{21}\)

b ) \(\frac{2}{5}+\frac{3}{5}\cdot\frac{4}{5}\)

\(=\frac{2}{5}+\frac{12}{25}\)

\(=\frac{10}{25}+\frac{12}{25}\)

\(=\frac{22}{25}\)

c )\(\frac{254\cdot399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+254}{254+399\cdot253}\)

\(=1\)

d )\(\frac{5932+6001\cdot5931}{5932\cdot6001-69}\)

\(=\frac{5932+6001\cdot5931}{5931\cdot6001+6001-69}\)

\(=\frac{5932+6001\cdot5931}{5931\cdot6001+5932}\)

\(=1\)

e )\(\frac{1}{5}\div\frac{2}{7}\)

\(=\frac{1}{5}\cdot\frac{7}{2}\)

\(=\frac{7}{10}\)

hok tốt nha