tim x,biet
5.(3-2x)+5(x-4)=6-4x
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NX
Tim x,
a,2x^4-6x^3+x^2+6x-3=0
b,x^3-9x^2+26x+24=0
c, P= 2x^4 - 4x^3 + 6x^2 - 4x + 5 biet rang x^2 - x=7
1
28 tháng 11 2016
a)\(2x^4-6x^3+x^2+6x-3=0\)
\(\Leftrightarrow2x^4-6x^3+3x^2-2x^2+6x-3=0\)
\(\Leftrightarrow x^2\left(2x^2-6x+3\right)-\left(2x^2-6x+3\right)=0\)
\(\Leftrightarrow\left(x^2-1\right)\left(2x^2-6x+3\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+1\right)\left(2x^2-6x+3\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1=0\\x+1=0\\2x^2-6x+3=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=-1\\\Delta_{2x^2-6x+3}=\left(-6\right)^2-4\left(2.3\right)=12\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=-1\\x_{1,2}=\frac{6\pm\sqrt{12}}{4}\end{array}\right.\)
b)\(x^3+9x^2+26x+24=0\)
\(\Leftrightarrow x^3+5x^2+6x+4x^2+20x+24=0\)
\(\Leftrightarrow x\left(x^2+5x+6\right)+4\left(x^2+5x+6\right)=0\)
\(\Leftrightarrow\left(x^2+5x+6\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+3\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+2=0\\x+3=0\\x+4=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-2\\x=-3\\x=-4\end{array}\right.\)
NM
0
24 tháng 1 2019
\(-4x\left(x-5\right)-2x\left(8-2x\right)=-3\)
\(\Leftrightarrow-4x^2+20x-16x+4x^2=-3\)
\(\Leftrightarrow4x=-3\Leftrightarrow x=\frac{-3}{4}\)
LT
1
19 tháng 10 2015
\(\frac{x}{4}=\frac{y}{3}\Rightarrow\frac{x}{12}=\frac{y}{9}\)
\(\frac{x}{3}=\frac{z}{5}\Rightarrow\frac{x}{12}=\frac{z}{20}\)
\(\Rightarrow\frac{x}{12}=\frac{y}{9}=\frac{z}{20}=\frac{2x-3y+z}{2\cdot12-3\cdot9+20}=\frac{6}{17}\)
\(\Rightarrow x=\frac{72}{17};y=\frac{54}{17};z=\frac{120}{17}\)
\(5\left(3-2x\right)+5\left(x-4\right)=6-4x\\ \Leftrightarrow15-10x+5x-20=6-4x\\ \Leftrightarrow-10x+5x+4x=6-15+20\\ \Leftrightarrow-x=11\\ \Leftrightarrow x=-11\)