Tìm số tự nhiên x biết rằng
b)ƯCLN (120,b)=15 và b <120
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Các số \(⋮\)15 và < 120 : 15; 30; 45; 60; 75; 90; 105
Vì 15 + 105 = 120
Nên a = 15 và b = 105 hoặc a = 105 và b = 15
vì ước chung lớn nhất của a và b là 15 nên
a= 15m
b = 15n
và 15m + 15n = 120
=> m + n = 8
tự tìm cặp m,n rồi thử nha bn
Tìm hai số tự nhiên a và b biết:
a) a + b = 120 và ƯCLN (a,b) = 15 b) a . b = 2592 và ƯCLN (a,b) = 12
a) \(\left(a,b\right)=15\Rightarrow a=15m,b=15n,\left(m,n\right)=1\).
\(a+b=15m+15n=120\Leftrightarrow m+n=8\)
Ta có bảng giá trị:
m | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
n | 7 | 6 | 5 | 4 | 3 | 2 | 1 |
a | 15 | loại | 45 | loại | 75 | loại | 105 |
b | 105 | 75 | 45 | 15 |
(các trường hợp loại do \(\left(m,n\right)\ne1\))
Vậy có các cặp \(\left(a,b\right)\)thỏa mãn là \(\left(15,105\right),\left(45,75\right),\left(75,45\right),\left(105,15\right)\).
b) Bạn làm tương tự.
a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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