Tính nhanh:
\(\dfrac{56^3+44^3}{100}-14.56\)
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45+55+100+56+44
=(45+55)+(56+44)+100
=100+100+100
=100.3
=300
k nha!!! hân hạnh
45+55+100+56+44
= (45+55)+(56+44)+100
=100+100+100
=300
tk mk nhé
Ta có: \(x+5^6:44=\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{3}{4}-\dfrac{15625}{44}\)
hay \(x=-\dfrac{3898}{11}\)
Vậy: \(x=-\dfrac{3898}{11}\)
\(x+\left(5^6:44\right)=\dfrac{3}{4}\)
\(x+\left(15625:44\right)=\dfrac{3}{4}\)
\(x+\dfrac{15625}{44}=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}-\dfrac{15625}{44}\)
\(x=\dfrac{-3898}{11}\)
c: \(\dfrac{12\cdot4\cdot72}{36\cdot2\cdot9}=\dfrac{1}{3}\cdot2\cdot8=\dfrac{16}{3}\)
\(\dfrac{-3}{5}+\dfrac{28}{5}.\left(\dfrac{43}{56}+\dfrac{5}{24}-\dfrac{21}{63}\right)\)
= \(\dfrac{-3}{5}+\dfrac{28}{5}.\dfrac{9}{14}\)
= \(\dfrac{-3}{5}+\dfrac{28.9}{5.14}\)
= \(\dfrac{-3}{5}+\dfrac{18}{5}\)
= \(\dfrac{\left(-3\right)+18}{5}\)
= \(\dfrac{15}{5}=3\)
2 + 4 + 6 + 8 + .... + 24 có số số hạng là:
(24 - 2) : 2 + 1 = 12 (số)
tổng là :
(24 + 2) x 12 : 2 = 156
\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{32}{40}+\dfrac{48}{56}+\dfrac{14}{21}\\ =\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{4}{5}+\dfrac{6}{7}+\dfrac{2}{3}\\ =\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{7}+\dfrac{6}{7}\right)+\left(\dfrac{1}{5}+\dfrac{4}{5}\right)\\ =1+1+1=3\)
Lời giải:
$\frac{1}{3}+\frac{1}{7}+\frac{1}{5}+\frac{32}{40}+\frac{48}{56}+\frac{14}{21}$
$=\frac{1}{3}+\frac{1}{7}+\frac{1}{5}+\frac{4}{5}+\frac{6}{7}+\frac{2}{3}$
$=(\frac{1}{3}+\frac{2}{3})+(\frac{1}{7}+\frac{6}{7})+(\frac{1}{5}+\frac{4}{5})$
$=\frac{3}{3}+\frac{7}{7}+\frac{5}{5}=1+1+1=3$
\(\dfrac{56^3+44^3}{100}-14.56\)
\(=\dfrac{\left(56+44\right)\left(56^2-56.44+44^2\right)}{100}-14.56\)
\(=\dfrac{100.\left(56^2-56.44+44^2\right)}{100}-14.56\)
\(=\)\(56^2-44.56+44^2-14.56\)
\(=\left(56^2-14.56\right)-\left(44.56-44^2\right)\)
\(=56\left(56-14\right)-44\left(56-44\right)\)