Question

[Nguyễn Thị Hồng Nhung]

Bài 1: Tính nhanh

a) \(\left(2017^1\right)^{2.4.6.8....2016}\)

b) \(2017^{\left(225-1^2\right).\left(225-2^2\right).\left(225-3^2\right)....\left(225-56^2\right)}\)

Bài 2: Tính

A = \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\): \(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)

B = \(\dfrac{4^6.9^5+6^9.1^{20}}{-8^4.3^{12}-6^{11}}\)

C = \(\dfrac{6^3+3.6^2+3^3}{-27}\)

D = \(\dfrac{1}{1-\dfrac{1}{1-2^{-1}}}\)+ \(\dfrac{1}{1+\dfrac{1}{1+2^{-1}}}\)

M = \(2^{10}-2^9-2^8-2^7-....-1\)

Giúp mk với. Mk cần gấp

Answer 1

[Trần Thiên Kim]

1b. Ta thấy \(225-15^2=0\)

Mọi số nhân với 0 đều = 0

=> \(2017^0=1\)

Answer 2

[Trần Thiên Kim]

2.

\(A=\dfrac{2.5^{22}-9.5^{21}}{25^{10}}:\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}=\dfrac{5^{21}\left(2.5-9\right)}{5^{20}}:\dfrac{5.7^{14}\left(3.7-19\right)}{7^{15}\left(7+3\right)}=5.1:\dfrac{5.7^{14}.2}{7^{15}.10}=5:\dfrac{1}{7}=35\)