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13 tháng 2 2016

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7 tháng 3 2017

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 Cho tam giác ABC có AB = AC = 10cm, BC = 12cm. Kẻ AH vuông góc với BC tại Ha) Chứng minh rằng H làtrung điểm của đoaṇ thẳng BCb) Tính độ dài đoạn thẳng AHc) Kẻ HI AB taị I và HK  AC taị K. Vẽ các điểm D và E sao cho I ,K lần lươṭ làtrung điểmcủa HD và HE. Chứng minh AE = AH . Tam giác ADE là tam giác gì? Vì sao?d) Chứng minh AH là đường trung trực của đoạn thẳng DE .e) Tìm điều kiện của tam giác...
Đọc tiếp

 

Cho tam giác ABC có AB = AC = 10cm, BC = 12cm. Kẻ AH vuông góc với BC tại H
a) Chứng minh rằng H là

trung điểm của đoaṇ thẳng BC

b) Tính độ dài đoạn thẳng AH
c) Kẻ HI AB taị I và HK  AC taị K. Vẽ các điểm D và E sao cho I ,K lần lươṭ là

trung điểm

của HD và HE. Chứng minh AE = AH . Tam giác ADE là tam giác gì? Vì sao?
d) Chứng minh AH là đường trung trực của đoạn thẳng DE .
e) Tìm điều kiện của tam giác ABC để A là trung điểm của DE

Cho tam giác ABC có AB = AC = 10cm, BC = 12cm. Kẻ AH vuông góc với BC tại H
a) Chứng minh rằng H là

trung điểm của đoaṇ thẳng BC

b) Tính độ dài đoạn thẳng AH
c) Kẻ HI AB taị I và HK  AC taị K. Vẽ các điểm D và E sao cho I ,K lần lươṭ là

trung điểm

của HD và HE. Chứng minh AE = AH . Tam giác ADE là tam giác gì? Vì sao?
d) Chứng minh AH là đường trung trực của đoạn thẳng DE .
e) Tìm điều kiện của tam giác ABC để A là trung điểm của DE

0
22 tháng 12 2016

(Đề hay quá!)

Gọi \(X\) là trung điểm \(BC\). CM được \(DF,AI,MN\) đồng quy tại điểm ta gọi là \(K\).

Theo tính chất đường trung bình ta có \(MN\) song song \(AB\).

Do tam giác \(ABC\) vuông tại \(A\) cũng suy ra \(AB\) song song với \(IE\).

Áp dụng định lí Thales liên tục ta có:

\(\frac{AN}{IE}=\frac{MN}{MI}=\frac{KA}{KI}=\frac{AP}{ID}\).

Do \(ID=IE\) nên \(AN=AP\). Kết thúc chứng minh.

22 tháng 12 2016

ê,chứng minh AI,DF,MX đồng quy kiểu gị ?

Bài 23 : Cho tam giác ABC vuông tại A ( AB < AC ) . Gọi F là trung điểm của BC , qua F kẻ đường thẳng d vuông góc và BC , đường thẳng d cắt đường thẳng AB , AC lần lượt tại D và E. a ) Chứng minh : tam giác AED đồng dạng với tam giác PEC b ) Chứng minh , BF.FC = DF.EF  c ) Tính BC biết DE = 5cm , EF = 4cm . d ) Gọi K là giao điểm của BE và DC , đường thẳng FK cắt AC tại I. Chứng minh : AC. EI = AE . IC   .Bài 26...
Đọc tiếp

Bài 23 : Cho tam giác ABC vuông tại A ( AB < AC ) . Gọi F là trung điểm của BC , qua F kẻ đường thẳng d vuông góc và BC , đường thẳng d cắt đường thẳng AB , AC lần lượt tại D và E. 

a ) Chứng minh : tam giác AED đồng dạng với tam giác PEC 

b ) Chứng minh , BF.FC = DF.EF 

 c ) Tính BC biết DE = 5cm , EF = 4cm 

. d ) Gọi K là giao điểm của BE và DC , đường thẳng FK cắt AC tại I. Chứng minh : AC. EI = AE . IC

 

 

 .Bài 26 : Cho  tam giác ABC vuông tại A , đường cao AH . Gọi E , F lần lượt là chân đường vuông góc kẻ tử H đến AB , AC 

a ) Chứng minh : AH = EF 

b ) Chứng minh : AB^2 = BH.BC 

c ) Chứng minh :tam giác HEF đồng dạng vớ itam giác  ABC 

d ) Kẻ tìa Bx vuông góc BC , Bx cắt đường thẳng AC tại K. Gọi O là giao điểm của EF và AH . Chứng minh : CO đi qua trung điểm của KB . 

 

 

Bài 27 : Cho tam giác ABC có góc A = 90 độ ; AB = 15cm , AC = 20cm , đường phân giác BD cắt đường cao AH tại K. 

a ) Tính BC , AD 

b ) Chứng minh tam giác AHB đồng dạng với tam giác CAB , 

c ) Chứng minh : BH.BD = BK.BA , d ) Gọi M là trung điểm của KD . Kẻ tia Bx song song với AM . Tia Bx cắt tia AH tại J , Chứng minh : HK.AJ = AK.HJ .

3
2 tháng 9 2020

Bài 26 :                                             Bài giải

a. Do AB⊥AC,HE⊥AB,HF⊥AC

⇒EAF^=AEH^=AFH^=90o

→◊AEHF là hình chữ nhật

2 tháng 9 2020

Bài 27 :                                                                  Bài giải

Hình : 

A B C D H K M x J

Còn bài giải tham khảo : Câu hỏi của nguyễn nhật trang nhung - Toán lớp 8 - Học toán với OnlineMath

Câu hỏi của nguyễn nhật trang nhung - Toán lớp 8 - Học toán với OnlineMath