45^3.20^4.18^2/180^5
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ta có tử =453x204x182=45x45x45x20x20x20x20x18x18
=45x45x45x4x5x4x5x4x5x4x5x18x18
=(45x4x45x4x45x4)x4x5x5x5x5x18x18
=(180x180x180)x4x5x5x5x5x9x2x9x2
=(180x180x180)x(4x5x9x2x2x5x9)x5x5
=(180x180x180x180x180)x25
=1805x25
lại có:180mũ5x25:180mux5=25
H= 45^3.20^4.18^2/ 180^5 = (3^2.5)^3.(2^2.5)^4.(2.3^2)^2/ (2^2.3^2.5)^5 = 3^6.5^3.2^8.5^4.2^2.3^4/ 2^10.3^10.5^5 = 3^10.5^7.2^10/ 2^10.3^10.5^5 = 5^2=25
G=(212.14.125):355.6
=\(\frac{\left(3.7\right)^2.7.2.5^{^3}}{\left(7.5\right)^5.2.3}\)=\(\frac{3^2.7^2.7.5^3}{7^5.5^5.3}\)=\(\frac{3}{7^2.5^2}\)=\(\frac{3}{49.25}\)=\(\frac{3}{1225}\)
\(G=\frac{21^2.14.125}{35^5.6}\)
\(G=\frac{\left(3.7\right)^2.7.2.5^3}{\left(7.5\right)^5.2.3}=\frac{3}{7^2.5^2}=\frac{3}{49.25}=\frac{3}{1225}\)
a: \(=\dfrac{2^{12}\cdot3^{14}}{3^{12}\cdot2^{12}}=3^2=9\)
b: \(=\dfrac{7^3\cdot2\cdot5^3}{5^2\cdot7^2\cdot6}=7\cdot5\cdot\dfrac{1}{3}=\dfrac{35}{3}\)
d: =2^5(2^8+1)/2^2(2^8+1)=2^3=8
c: \(=\dfrac{5^3\cdot3^6\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}=5^2\)
\(C=\frac{21^2.14.125}{35^3.6}\)
\(C=\frac{\left(3.7\right)^2.2.7.5^3}{\left(5.7\right)^3.2.3}\)
\(C=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)
\(C=\frac{3^2.7^3.2.5^3}{5^3.7^3.2.3}=3\)
\(D=\frac{45^3.20^4.18^2}{180^5}\)
\(D=\frac{\left(5.3^2\right)^3.\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)
\(D=\frac{5^3.3^6.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)
\(D=\frac{5^7.3^{10}.2^{10}}{2^{10}.3^{10}.5^5}=5^2=25\)
\(\frac{21^2\cdot14\cdot125}{35^2\cdot6}=\frac{3^2\cdot7^2\cdot2\cdot25\cdot3}{5^2\cdot7^2\cdot2\cdot3}=\frac{3^4\cdot7^2\cdot2\cdot5^2}{5^2\cdot7^2\cdot2\cdot3}=3^3=27..\)
\(\frac{45^3\cdot20^4\cdot18^2}{180^5}=\frac{5^3\cdot9^3\cdot4^4\cdot5^4\cdot2^2\cdot9^2}{2^{10}\cdot3^{10}\cdot5^5}=\frac{5^7\cdot9^5\cdot4^4}{4^5\cdot9^5\cdot5^5}=\frac{1}{4}=0.25\)
d) Ta có: \(D=\dfrac{21^2\cdot14\cdot125}{35^3\cdot6}\)
\(=\dfrac{7^2\cdot3^2\cdot7\cdot2\cdot5^3}{5^3\cdot7^3\cdot6}\)
\(=\dfrac{3^2\cdot2}{6}=\dfrac{6\cdot3}{6}=3\)
e) Ta có: \(E=\dfrac{45^3\cdot20^4\cdot18^2}{180^5}\)
\(=\dfrac{3^6\cdot5^3\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}\)
\(=\dfrac{3^{10}\cdot5^7\cdot2^{10}}{2^{10}\cdot3^{10}\cdot5^5}=25\)
f) Ta có: \(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}\)
\(=\dfrac{2^5\left(2^8+1\right)}{2^2\left(2^8+1\right)}=\dfrac{2^5}{2^2}=\dfrac{32}{4}=8\)
A = \(\dfrac{72^3.5^{42}}{108^4}\)
= \(\dfrac{\left(2^3.3^2\right)^3.5^{42}}{\left(2^2.3^3\right)^4}\)
= \(\dfrac{2^9.3^6.5^{42}}{2^8.3^{12}}\)
= \(\dfrac{2.5^{42}}{3^6}\)
@trần phúc nguyên
B = \(\dfrac{45^3.20^4.18^2}{180^5}\)
= \(\dfrac{\left(3^2.5\right)^3\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)
= \(\dfrac{3^6.5^3.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)
= \(\dfrac{3^{10}.5^7.2^{10}}{2^{10}.3^{10}.5^5}\)
= 25
@trần phúc nguyên
453 = (9.5)3 = 36.53
204 = (4.5)4 = 28.54
182 = (9.2)2 = 34.22
1805 = (4.9.5)5 = 210.310.55
\(=\dfrac{3^6.5^3.2^8.5^4.3^4.2^2}{2^{10}.3^{10}.5^5}=\dfrac{2^{10}.3^{10}.5^7}{2^{10}.3^{10}.5^5}=5^2=25\)
\(B=\dfrac{11.3^{29}-3^{30}}{4.3^{28}}=\dfrac{3^{29}\left(11-3\right)}{3^{28}.4}=\dfrac{3.8}{4}=6\)