0.4x\(^2\)- 4x- 1200 = 0
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a, (-0,4x-2)0(1.5x+1)-(-4x-0.8)=3.6
<=>-0,4x-2-1,5x-1+4x+0.8=3,6
<=>2,1x+2,2=3,6
<=>2,1x=1,4
<=>x=2/3
\(\begin{array}{l} a)3x - 1 = x + 3\\ \Leftrightarrow 3x - x = 3 + 1\\ \Leftrightarrow 2x = 4\\ \Leftrightarrow x = 2\\ b)15 - 7x = 9 - 3x\\ \Leftrightarrow - 7x + 3x = 9 - 15\\ \Leftrightarrow - 4x = - 6\\ \Leftrightarrow x = \dfrac{3}{2}\\ c)x - 3 = 18\\ \Leftrightarrow x = 18 + 3\\ \Leftrightarrow x = 21 \end{array}\)
\(\begin{array}{l} d)2x + 1 = 15 - 5x\\ \Leftrightarrow 2x + 5x = 15 - 1\\ \Leftrightarrow 7x = 14\\ \Leftrightarrow x = 2\\ e)3x - 2 = 2x + 5\\ \Leftrightarrow 3x - 2x = 5 + 2\\ \Leftrightarrow x = 7\\ f) - 4x + 8 = 0\\ \Leftrightarrow - 4x = - 8\\ \Leftrightarrow x = 2 \end{array}\)
\(\frac{3}{5}x+\frac{2}{5}x+\frac{x}{3}=2\)
\(x+\frac{x}{3}=2\)
\(\frac{4}{3}x=2\)
\(x=2:\frac{4}{3}=\frac{3}{2}\)
\(60\%x+0,4.x+\frac{x}{3}=2\)
\(\frac{3}{5}.x+\frac{2}{5}.x+\frac{1}{3}.x=2\)
\(x.\left(\frac{3}{5}+\frac{2}{5}+\frac{1}{3}\right)=2\)
\(x.\frac{4}{3}=2\)
\(x=2:\frac{4}{3}\)
\(x=\frac{3}{2}=1,5\)
60% x + 0,4x + x : 3 = 2
3/5 . x + 2/5 . x + x : 3 = 2
(3/5 + 2/5) x + x : 3 = 2
x + x : 3 = 2
x : (1 + 3) = 2
x : 4 = 2
x = 8
\(P=\dfrac{\sqrt{x}}{\sqrt{x}+3}:\dfrac{2\sqrt{x}}{\sqrt{x}-3}-\dfrac{3x+9}{x-9}\)
\(=\dfrac{\sqrt{x}-3}{2\left(\sqrt{x}+3\right)}-\dfrac{3x+9}{x-9}\)
\(=\dfrac{x-9-3x-9}{2\left(x-9\right)}=\dfrac{-2x-18}{2\left(x-9\right)}=\dfrac{-x-9}{x-9}\)
\(-27x^2+257-1200=-\left(3\sqrt{2}x-\dfrac{256}{6\sqrt{3}}\right)^2-\dfrac{16016}{27}< 0\forall x\)
\(\Rightarrow\) phương trình vô nghiệm
0,4x2 - 4x -1200 =0
\(\Delta=b^2-4ac\) = (-4)2 - 4. (1200) . 0,4 = 1936
=> pt có 2 nghiệm phân biệt.
x1= \(\dfrac{-\left(-4\right)-\sqrt{1936}}{0,4}\)= 100
x2=\(\dfrac{-\left(-4\right)+\sqrt{1936}}{0,4}\)= 120