C = \(\dfrac{4^9.36+64^4}{16^4.100}\)
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A=4^9.36+64^4/16^4.100
A= 262144.36+256.100
A=9437184+25600
A=9462784
\(A=\frac{4^9.36+64^4}{16^4.100}=\frac{2^{20}.\left(9+16\right)}{2^{18}.5^2}=\frac{2^{20}.5^2}{2^{18}.5^2}=2^2=4\)
a, \(B=\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(=\dfrac{2^{10}.\left(13+65\right)}{2^8.2^3.13}\)
\(=\dfrac{2^{10}.78}{2^{11}.13}\)\(=\dfrac{1.6}{2.1}=\dfrac{1.3}{1.1}=3\)
b: \(=\dfrac{2^{20}\cdot3^2+2^{54}}{2^{18}\cdot5^2}=\dfrac{2^{20}\left(3^2+2^{32}\right)}{2^{18}\cdot5^2}=\dfrac{2^2\left(3^2+2^{32}\right)}{25}\)
c: \(=\dfrac{2^9\cdot3^6\cdot3^6\cdot2^2}{2^8\cdot3^{12}}=\dfrac{2^{11}}{2^8}=8\)
d: \(=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}=9\)
B = 4^9.36+64^4
16^4.100
B = 2^20.(9+16)
2^18.5^2
B = 2^20.5^2
2^18.5^2
B = 2^2
B = 4
D = 4^6.3^4.9^5
6^12
D = 2^12.3^4.9^5
2^12.3^12
D = 2^12.3^14
2^12.3^12
D = 3^2
D = 9
\(\frac{4^9.36+64^4}{16^4.100}=\frac{4^{10}\left(9+8\right)}{4^{10}.25}=\frac{17}{25}\)
Câu 1: \(\frac{4^9.36+64^4}{16^4.100}=\frac{4^9.36+4^{12}}{4^8.4.5^2}=\frac{4^9\left(36+4^3\right)}{4^9.25}=\frac{4^9.100}{4^9.25}=\frac{100}{25}=4\)
Câu 2: \(\frac{125^5-25^5}{100.50^5-10^2}=\frac{25^5.5^5-25^5}{25.4.25^5.2^5-25.4}=\frac{25^5\left(5^5-1\right)}{100\left(25^5.2^5-1\right)}\)
Câu 2 sai đề hay sao á bạn mk làm ko ra!
\(C=\dfrac{4^9.36+64^4}{16^4.100}=\dfrac{4^9.36+4^{12}}{4^9.25}=\dfrac{4^9\left(36+4^3\right)}{4^9.25}=\dfrac{100}{25}=4\)