1. Tính tổng
a) A= 7/10.11 + 7/11.12 + 7/12.13 + ... + 7/69.70
b) B = 1/25.27+1/27.29+1/29.31+...+ 1/73.75
2. CMR:
2/1.3+2/3.5+2/5.7+2/99.101 < 1
3. Tìm x:
a) 3x + 1/2 = 3/4
b) (x-3) - 1/2 = 2/3
c) x+3/15 = 1/3
d) (3x-2)^3 = 64
e) (2x-3)^2 = 25
g) GTTĐ của x+3 - 1/2 = 2/3
4.Cho 2 tia Ox và Oy đối nhau.Vẽ tia Oz sao cho góc yOz = 40 độ.
a) Trong 3 tia,tia nào nằm giữa 2 tia còn lại?Tính góc xOz
b) Gọi Om là T.P.Giác của góc xOz.Tính góc mOy?
5. Vẽ 2 góc kề bù aOb và aOc sao cho aOc = 80 độ.
a) Tính aOb?
b) Trên nửa mặt phẳng bờ BC; vẽ tia Od sao cho bOd = 140 độ. Chính tỏ rằng Od là T.P.Giác của góc aOc?
Mấy bạn giúp mình nha.Cảm ơn rất nhiều nè <3
Bạn nào nhanh và đúng nhất mình sẽ tặng 3 ticks nhá.Thanks <3
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Tính :
a) \(M=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}\)
\(=\frac{100}{101}\)
b) \(A=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)
\(=7.\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)
\(=7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(=7.\left(\frac{1}{10}-\frac{1}{70}\right)\)
\(=7.\frac{3}{35}\)
\(=\frac{3}{5}\)
c) \(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)
\(=\frac{1}{2}.\left(\frac{2}{25.27}+\frac{2}{27.29}+\frac{2}{29.31}+...+\frac{2}{73.75}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(=\frac{1}{2}.\frac{2}{75}\)
\(=\frac{1}{75}\)
1) A=7/10.11+7/11.12+7/12.13+...+7/69.70
A=7.(1/10.11+1/11.12+1/12.13+...+1/69.70)
A= 7.(1/10-1/11+1/11-1/12+1/12-1/13+...+1/69-1/70)
A= 7.(1/10-1/70)
A=7.3/35=3/5
2)B=1/25.27+1/27.29+1/29.31+...+1/73.1/75
B=1/25-1/27+1/27-1/29+1/29-1/31+...+1/73-1/75
B=1/25-1/75=2/75
A = 7/ 10.11 + 7/ 11.12 + 7/ 12.13 + .... + 7/69.70
(1/7).A=1/10.11+1/11.12+...+1/69.70
=1/10-1/11+1/11-1/12+...+1/69-1/70
=1/10-1/70=3/35
=>A=7.(3/35)
=3/5
2 ) B = 1/ 25.27 + 1/ 27.29 + 1/29.31+ ......+ 1/ 73.75
=>(1/2).B=2/25.27+...+2.73.75
=1/25-1/27+...+1/73-1/75
=1/25-1/75
=2/75
=>B=4/75
\(A=7\left(\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}+...+\dfrac{1}{69}-\dfrac{1}{70}\right)\)
\(=7\left(\dfrac{1}{10}-\dfrac{1}{70}\right)=\dfrac{7.60}{700}=\dfrac{420}{700}=\dfrac{3}{5}\)
\(B=\dfrac{1}{2}\left(\dfrac{1}{25}-\dfrac{1}{27}+\dfrac{1}{27}-\dfrac{1}{29}+...+\dfrac{1}{73}-\dfrac{1}{75}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{25}-\dfrac{1}{75}\right)=\dfrac{1}{75}\)
a) a)A=7/10.11+7/11.12+7/12.13+...+7/69.70
=7.1/10.11.1+...+7.1/69.70.1
=7/1.1/10.11+...+7/1.1/69.70
=7/1.(1/10.11+...+1/69.70)
=7/1.(1/10-1/11+...+1/69-1/70)
=7/1.(1/10-1/70)
=7/1.(70/70-1/70)
=7/1.69/70
=69/10
C=4/2.4+4/4.6+4/6.8+...+4/2008.2010
C = 2 ( 2 / 2.4 + 2/4.6 + 2/6.8 + ...+2/2008.2010)
C = 2 ( 1 - 1/4 + 1/4 - 1/6+1/6 - 1/8 +....+1/2008 - 1/2010 )
C = 2 ( 1 - 1 / 2010 )
C = 2 . 2009/2010
C = 2009 / 1005
Chúc bạn học tốt !
A = \(\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)
=\(7\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)
=\(7\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)
=\(7\left(\frac{1}{10}-\frac{1}{70}\right)\)
=\(7.\frac{3}{35}\)
=\(\frac{3}{5}\)
B=\(\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)
=\(\frac{1}{2}\left(\frac{2}{25.27}+\frac{2}{27.29}+\frac{2}{29.31}+...+\frac{2}{73.75}\right)\)
=\(\frac{1}{2}\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
=\(\frac{1}{2}\left(\frac{1}{25}-\frac{1}{75}\right)\)
=\(\frac{1}{2}.\frac{2}{75}\)
=\(\frac{1}{75}\)
Bài 1 :
a) Ta có :
\(A=\dfrac{7}{10.11}+\dfrac{7}{11.12}+\dfrac{7}{12.13}+................+\dfrac{7}{69.70}\)
\(A=7\left(\dfrac{1}{10.11}+\dfrac{1}{11.12}+\dfrac{1}{12.13}+................+\dfrac{1}{69.70}\right)\)
\(A=7\left(\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}+..............+\dfrac{1}{69}-\dfrac{1}{70}\right)\)
\(A=7\left(\dfrac{1}{10}-\dfrac{1}{70}\right)\)
\(A=7.\dfrac{3}{35}=\dfrac{21}{35}\)
b) Ta có :
\(B=\dfrac{1}{25.27}+\dfrac{1}{27.29}+\dfrac{1}{29.31}+..............+\dfrac{1}{73.75}\)
\(2B=\dfrac{2}{25.27}+\dfrac{2}{27.29}+..............+\dfrac{2}{73.75}\)
\(2B=\dfrac{1}{25}-\dfrac{1}{27}+\dfrac{1}{27}-\dfrac{1}{29}+...........+\dfrac{1}{73}-\dfrac{1}{75}\)
\(2B=\dfrac{1}{25}-\dfrac{1}{75}=\dfrac{2}{75}\)
Mk mới làm dc bài 1 thôi, xin lỗi bn nha!!
~ Chúc bn học tốt ~
Bài 2 :
Đặt :
\(A=\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...........+\dfrac{2}{99.101}\)
\(A=\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+.............+\dfrac{1}{99}-\dfrac{1}{101}\)
\(A=\dfrac{1}{1}-\dfrac{1}{101}=\dfrac{100}{101}\)
Vì \(\dfrac{100}{101}< 1\Rightarrow A< 1\rightarrowđpcm\)
~ Chúc bn học tốt ~