tìm y:a)y-6:2-(48-24x2:6-3)=0 b)(7x13+8x13):(9 2/3-y)=39
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\(a,\)\(y-\frac{6}{2}-\left(48-24\times\frac{2}{6}-3\right)=0\)
\(\Rightarrow y-3-\left(48-8-3\right)=0\)
\(\Rightarrow y-3-48+8+3=0\)
\(\Rightarrow y-40=0\)
\(\Rightarrow y=40\)
1 )
= (1 + 3+ 5+ .....+2003+2005) \(\times\)( 125 nhân 1001 NHÂN 127 - 127 nhân 1001 nhân 125 )
= (1 + 3+ 5+ .....+2003+2005) \(\times\)0
= 0
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Trả lời:
Bài 1
\(\left(1+3+5+...+2003+2005\right)\times\left(125125\times127-127127\times125\right)\)
\(=\left\{\left(2005+1\right)\times\left[\left(2005-1\right)\div2+1\right]\div2\right\}\times\left(125\times1001\times127-127\times1001\times125\right)\)
\(=\left(2006\times1003\div2\right)\times0\)
\(=10061009\times0\)
\(=0\)
Bài 2
\(y-6\div2-\left(48-24\times2\div6-3\right)=0\)
\(y-3-\left(48-8-3\right)=0\)
\(y-3-37=0\)
\(y-40=0\)
\(y=40\)
Vậy \(y=40\)
y - 6 : 2 - ( 48 - 48 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 8 - 3 ) = 0
y - 6 : 2 - 37 = 0
y - 3 - 37 = 0
y = 37 + 3
y = 40
a) y - 6 chia 2 - ( 48 - 24 x 2 chia 6 - 3 ) = 0
=> y - 6 chia 2 - ( 48 - 48 chia 6 - 3 ) = 0
=> y - 6 chia 2 - ( 48 - 8 -3 ) = 0
= > y - 6 chia 2 - 37 = 0
=> y - 6 chia 2 = 0 + 37
=> y - 6 chia 2 = 37
=> y -6 = 37 chia 2
=> y - 6 = 37 / 2
=> y = 37 / 2 + 6
=> y = 49 / 2
Vậy y = 49 / 2
b) ( 7 x 13 + 8 x 13 ) chia ( 92 /3-y ) = 39
=> ( 91 + 104 ) chia ( 92/3 - y ) =39
=> 195 chia ( 92 /3 - y ) = 39
=> 92/3 - y = 7605
=> y = 7605 + 92/3
=> y = 22907 /3
Vậy y = 22907 / 3
a) \(y-6:2-\left(48-24.2:6-3\right)=0.\)
\(\Rightarrow y-3-\left(48-8-3\right)=0\)
\(\Rightarrow y-3-37=0\)
\(\Rightarrow y=0+37+3=40\)
Vậy y = 40
b) \(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow\frac{29}{3}-y=195:39=5\)
\(\Rightarrow y=\frac{29}{3}-5=\frac{14}{3}\)
Vậy y=\(\frac{14}{3}\)
a) y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 48 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 8 - 3 ) = 0
y - 6 : 2 - 37 = 0
y - 3 = 0 + 37
y - 3 = 37
y = 37 + 3
y = 40
b) ( 7 x 13 + 8 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
( 15 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
195 : ( \(9\frac{2}{3}\) - y ) = 39
\(9\frac{2}{3}\) - y = 195 : 39
\(9\frac{2}{3}-y=5\)
\(y=9\frac{2}{3}-5\)
\(y=\frac{14}{3}\)
a: =>y-3-(48-48:6-3)=0
=>y-3-48+8+3=0
=>y-40=0
hay y=40
b: =>15x13:(29/3-y)=39
=>29/3-y=5
hay y=14/3