Tìm x
7 . x - 2. x = 6^17 : 6^15 + 44 : 11
100 - ( 2 . x + 6) . 2 = 4^2
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7x - 2x = 617 - 615 + 44 : 11
x( 7 - 2 ) = 617 - 15 + 4
5x = 62 + 4
5x = 36 + 4
5x = 40
x = 40 : 5
x = 8
a) 7.x - x = 521 : 519 + 3.22 - 70
6x = 25 + 12 - 1
6x = 36
x = 6
b) 7x - 2x = 617 : 615 + 44 : 11
5x = 36 + 4
5x = 40
x = 8
c) 5x + x = 39 - 311 : 39
6x = 39 - 9
6x = 30
x = 5
d) [(6x - 39) : 7]. 4 = 12
(6x - 39) : 7 = 12 : 4
(6x - 39) : 7 = 3
6x - 39 = 3 . 7
6x - 39 = 21
6x = 21 + 39
6x = 60
x = 10
x =
`1, -2/9 xx 15/17 + (-2/9) xx 2/17`
`= -2/9 xx (15/17 + 2/17)`
`= -2/9 xx 17/17`
`=-2/9xx1`
`=-2/9`
__
`-5/3 xx 6/5 + (-7/9) xx 3/10`
`= -30/15 + (-21/90)`
`= -2 + (-7/30)`
`=-60/30 +(-7/30)`
`=-67/30`
__
`15/20 xx 7/5 + (-9/7) xx (-6/4)`
`=3/4 xx7/5 + (-9/7) xx(-6/4)`
`= 21/20 + 54/28`
`= 21/20 + 27/14`
`=417/140`
__
`-25/13 xx 5/19 + (-25/13) xx 14/19`
`=-25/13 xx (5/19 +14/19)`
`=-25/13 xx 19/19`
`= -25/13 xx 1`
`=-25/13`
__
`-7/13 xx 13/5 + (-9/7) xx 5/3`
`=-7/5 +(-15/7)`
`=-124/35`
A, 7x - x = 5^21 : 5^19 + 3 . 2^2 - 7^0
6x = 5^2 + 3 . 4 - 1
6x = 25 + 12 - 1
6x = 37 - 1
6x = 36
x = 6.
B, mình giải ra nhưng số to quá. Bạn thử kiểm tra lại đề xem.
C, 7x - 2x = 6^17 : 6^15 + 44 : 11
5x = 6^2 + 4
5x = 40
x = 8.
\(a.\)\(7x-2x=6^{17}:6^{15}+44:11\)
\(\Leftrightarrow5x=6^2+4\)
\(\Leftrightarrow5x=36+4\)
\(\Leftrightarrow5x=40\)
\(\Leftrightarrow x=40:5\)
\(\Leftrightarrow x=8\)
\(b.\)\(9^{x-1}=9\)
\(\Leftrightarrow9^x:9=9\)
\(\Leftrightarrow9^x=81\)
\(\Leftrightarrow9^x=9^2\)
\(\Leftrightarrow x=2\)
\(c.\)\(\left|x-5\right|=7-\left(-3\right)\)
\(\Leftrightarrow\left|x-5\right|=7+3\)
\(\Leftrightarrow\left|x-5\right|=10\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=10\\x-5=-10\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=15\\x=-5\end{cases}}\)
\(d.\)\(\left|x-5\right|=\left|-7\right|\)
\(\Leftrightarrow\left|x-5\right|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=7\\x-5=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=12\\x=-2\end{cases}}\)
\(e.\)\(\left|x\right|-5=3\)
\(\Leftrightarrow\left|x\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x=8\\x=-8\end{cases}}\)
\(g.\)\(15-2\left|x\right|=13\)
\(\Leftrightarrow2\left|x\right|=15-13=2\)
\(\Leftrightarrow\left|x\right|=2:2=1\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)
\(h.\)\(\left|x-2\right|=0\)
\(\Leftrightarrow x-2=0\)
\(\Leftrightarrow x=0+2\)
\(\Leftrightarrow x=2\)