Giải giúp mình với
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7 tháng 11 2021
\(ĐK:x\ge\dfrac{1}{2}\\ PT\Leftrightarrow4\sqrt{2x-1}+3\sqrt{2x-1}=4\\ \Leftrightarrow\sqrt{2x-1}=\dfrac{4}{7}\\ \Leftrightarrow2x-1=\dfrac{16}{49}\\ \Leftrightarrow x=\dfrac{65}{98}\left(tm\right)\)
LC
7 tháng 11 2021
\(\sqrt{32x-16}+\sqrt{18x-9}=4\) (ĐKXĐ: x≥\(\dfrac{1}{2}\))
⇔ \(\sqrt{16\left(2x-1\right)}+\sqrt{9\left(2x-1\right)}=4\)
⇔ 4\(\sqrt{2x-1}\)\(+3\sqrt{2x-1}\)= 4
⇔ 7\(\sqrt{2x-1}=4\)
⇔ \(\sqrt{2x-1}=\dfrac{4}{7}\)
⇔ \(2x-1=\dfrac{16}{49}\)
⇔ 2x = \(\dfrac{65}{49}\)
⇔ x = \(\dfrac{65}{98}\) (TM)
Vậy x = \(\dfrac{65}{98}\)
các bạn giải giúp mình vơi
TD
1 tháng 4 2023
0,75x-3,5=-0,25x
0,75x+0,25x=3,5
x(0,75+0,25)=3,5
x.1=3,5
x=3,5
Chúc bạn học tốt!
mn giải giúp em vơi ạ em đang cần gấp cảm ơn
TY
27 tháng 1 2019
\(\frac{7}{y+4}=\frac{63}{117}\)\(\Rightarrow63\cdot\left(y+4\right)=7\cdot117\)
\(\Rightarrow63y+63\cdot4=819\)
\(\Rightarrow63y+252=819\)
\(\Rightarrow63y=819-252\)
\(\Rightarrow63y=567\)
\(\Rightarrow y=\frac{567}{63}\)
\(\Rightarrow y=9\)
Vậy y=9
(các bạn nhớ cho mk nha )
EX4:
1. go to the school cafeteria
-> Let's go to the school cafeteria
-> What about going to the school cafeteria
-> Why don't we go to the school cafeteria
2. eat in fast food restaurant
-> Let's eat in fast food restaurant
-> What about eating in fast food restaurant
-> Why don't we eat in fast food restaurant
3. do homework together
-> Let's do homework together
-> What about doing homework together
-> Why don't we do homework together
4. play table tennis
-> Let's play table tennis
-> What about playing table tennis
-> Why don't we play table tennis
5. go to the beach
-> Let's go to the beach
-> What about going to the beach
-> Why don't we go to the beach
6. go shopping
-> Let's go shopping
-> What aboutgoing shopping
-> Why don't we go shopping
bài 3 hay bài 4 z bn