Tính:
A= (5-15625)2015. (52-15625)2015. (53-15625)2015... .(52016-15625)2015.
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a/A=1+2+4+8+...+1024
2A=2+4+8+16+....+2048
2A-A=(2+4+8+16+....+2048)-(1+2+4+8+...+1024)
A=2048-1
A=2047
VẬY A=2047
b/B=1+5+25+125+....+15625
5B=5+25+125+625+....+78125
5B-B=(5+25+125+625+....+78125)-(1+5+25+125+....+15625)
4B=78125-1
4B=78124
B=78124:4
B=19531
VẬY B =19531
C=1/1.2+1/2.3+1/3.4+...+1/2015.2016
C=1-1/2+1/2-1/3+1/3-1/4+...+1/2015-1/2016
=1-1/2016
=2015/2016
VẬY C=2015/2016
D/=10/1.3+10/3.5+10/5.7+....+10/2013.2015
=5(2/1.3+2/3.5+2/5.7+...+2/2013.2015)
=5(1-1/3+1/3-1/5+1/5-1/7+..+1/2013-1/2015)
=5(1-1/2015)
=5.2014/2015
=2014/403
VẬY D=2014/403
a, A = 1 + 2 + 4 + 8 +...+ 1024
\(A=1+2+2^2+2^3+....+2^{10}\)
\(2A=2+2^2+2^3+....+2^{10}+2^{11}\)
\(A=1+2+2^2+2^3+....+2^{10}\)
\(A=2^{11}-1=2047\)
b, B = 1 + 5 + 25 + 125 + ... + 15625
\(B=1+5+5^2+5^3+....+5^6\)
\(3B=5+5^2+5^3+....+5^6+5^7\)
\(B=1+5+5^2+5^3+....+5^6\)
\(2B=5^7-1\Rightarrow B=\frac{5^7-1}{2}=39062\)
d, D = 10 / 1 . 3 + 10 / 3 . 5 + 10 / 5 . 7 + ... + 10 / 2013 . 2015
\(D=\frac{10}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{2013.2015}\right)\)
\(D=\frac{10}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{2013}-\frac{1}{2015}\right)\)
\(D=\frac{10}{2}.\left(1-\frac{1}{2015}\right)=5.\frac{2014}{2015}=\frac{2014}{403}\)
Câu c thì tương tự
\(=1+5+5^2+...+5^6+5^7\\ \text{Đặt }A=1+5+5^2+...+5^7\\ \Leftrightarrow5A=5+5^2+...+5^8\\ \Leftrightarrow4A=5^8-1\\ \Leftrightarrow A=\dfrac{5^8-1}{4}=97656\)
\(5\cdot x\cdot15625=625\)
\(5\cdot x=625:15625\)
\(\Rightarrow x=\frac{1}{25}:5=\frac{1}{125}\)
5xS=1+1/5+1/25+....+1/3125
5xS-S=(1+1/5+1/25+...+1/3125)-(1/5+1/25+1/125+....+1/15625)
4xS=1-1/15625=15624/15625
1xS=15624/15625:4=15624/15625x1/4=15624/62500=3906/15625
ấy ấy, đừng coi thường mk vậy chứ, bài này dễ mà
A= (5-15625).2015.(52-15625).2015.(53-15625).2015...(52016-15625).2015
A= (5-15625).2015.(52-15625).2015.(53-15625).2015...(56-15625).2015...(52016.15625).2015
A= (5-15625).2015.(52-15625).2015.(53-15625).2015...(15625-15625).2015...(52016.15625).2015
A= (5-15625).2015.(52-15625).2015.(53-15625).2015...0.2015...(52016.15625).2015
A= 0