-5/7 * 2/11 + -5/7 * 9/14 + 12/7
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\(\frac{5}{7}.\frac{12}{11}+\frac{9}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
\(=\frac{1}{7}.\frac{1}{11}.\left(5.12+9.2-5.14\right)\)
\(=\frac{1}{77}.\left(60+18-70\right)\)
\(=\frac{1}{77}.8=\frac{8}{77}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,-\dfrac{5}{9}+\dfrac{14}{9}=\dfrac{-5+14}{9}=\dfrac{9}{9}=1\\ b,\dfrac{2}{7}+\dfrac{8}{-3}\\ =\dfrac{2}{7}-\dfrac{8}{3}\\ =\dfrac{2.3-8.7}{21}\\ =\dfrac{6-56}{21}\\ =\dfrac{-50}{21}\\ c,\dfrac{9}{11}+\dfrac{5}{7}+\dfrac{20}{-11}+\dfrac{12}{25}+\dfrac{2}{7}\\ =\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{9}{11}-\dfrac{20}{11}\right)+\dfrac{12}{25}\\ =\dfrac{7}{7}-\dfrac{11}{11}+\dfrac{12}{25}\\ =1-1+\dfrac{12}{25}\\ =\dfrac{12}{25}\)
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\(\dfrac{9}{14}-\dfrac{5}{8}+\dfrac{3}{7}=\dfrac{36}{56}-\dfrac{35}{56}+\dfrac{24}{56}=\dfrac{25}{56}\)
\(\dfrac{2}{9}-\dfrac{7}{10}+\dfrac{4}{5}=\dfrac{20}{90}-\dfrac{63}{90}+\dfrac{72}{90}=\dfrac{29}{90}\)
\(\dfrac{8}{19}+\dfrac{7}{5}-\dfrac{9}{20}+\dfrac{11}{12}=\dfrac{8}{19}+\dfrac{84}{60}-\dfrac{27}{60}+\dfrac{55}{60}=\dfrac{8}{19}+\dfrac{112}{60}=\dfrac{8}{19}+\dfrac{28}{15}=\dfrac{652}{285}\)
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\(-\dfrac{11}{12}+\dfrac{7}{8}+\dfrac{1}{10}\)
\(=-\dfrac{1}{24}+\dfrac{1}{10}\)
\(=\dfrac{7}{120}\)
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a: =-5-7-8-3=-26
b: =-4-2-5-6=-17
c: =-8-11-4-2=-25
d: -9-15-6-3=-30
e: =-12-9-3-8=-32
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(5/7 + 9/7 - 5/7) = 9/7
12/11 + 2/11 - 14/11 =1
9/7 x 1 = 9/7
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\dfrac{-7}{11}=-\dfrac{5}{11}\)
b: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\left(4+\dfrac{3}{8}\right)\)
\(=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{3}{2}\cdot5=\dfrac{15}{2}\)
c: \(=\dfrac{2}{15}-\dfrac{2}{15}\cdot5+\dfrac{3}{15}=\dfrac{2}{15}\cdot\left(-4\right)+\dfrac{3}{15}=\dfrac{-8+3}{15}=\dfrac{-5}{15}=-\dfrac{1}{3}\)
d: \(=\dfrac{4}{9}\left(19+\dfrac{1}{3}-39-\dfrac{1}{3}\right)=\dfrac{4}{9}\cdot\left(-20\right)=-\dfrac{80}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\frac{7}{5}+\frac{9}{7}+\frac{6}{5}+\frac{11}{7}\)
C1: \(\frac{94}{35}+\frac{6}{5}+\frac{11}{7}=\frac{136}{35}+\frac{11}{7}=5\frac{16}{35}\)
C2: \(=\left(\frac{7}{5}+\frac{6}{5}\right)+\left(\frac{9}{7}+\frac{11}{7}\right)=\frac{13}{5}+\frac{20}{7}=5\frac{16}{35}\)
b,
C1 : \(\frac{8}{14}+\frac{2}{11}+\frac{12}{14}+\frac{31}{11}=\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\frac{58}{77}+\frac{6}{7}+\frac{31}{11}=\frac{124}{77}+\frac{31}{11}=4\frac{3}{7}\)
C2:
\(\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\left(\frac{4}{7}+\frac{6}{7}\right)+\left(\frac{2}{11}+\frac{31}{11}\right)=\frac{10}{7}+3=3\frac{10}{7}=4\frac{3}{7}\)
**** cko t nha , xin xin đó
Thế thì mình giải theo đề mình nhé, chứ đề bạn sai rồi, không tính nhanh được.
\(A=-\frac{5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\\ =-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\\ =-\frac{5}{7}.1+\frac{12}{7}\\ =\frac{12}{7}-\frac{5}{7}\\ =\frac{12-5}{7}\\ =\frac{7}{7}=1\)
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12/7 là phân số hay hốn số vậy bạn?