Tìm x:\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)
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TN
2
DN
26 tháng 8 2015
\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)
\(\Leftrightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{28}-1=0\)
\(\Leftrightarrow\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\Leftrightarrow\left(x-124\right)\left(\frac{1}{24}+\frac{1}{26}+\frac{1}{28}\right)=0\)
Mà 1/24+1/26+1/28 khác 0
\(\Leftrightarrow x-124=0\Leftrightarrow x=124\)
D
26 tháng 8 2018
\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)
\(\Leftrightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{28}-1=0\)
\(\Leftrightarrow\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\Leftrightarrow\left(x-124\right)\left(\frac{1}{24}+\frac{1}{26}+\frac{1}{28}\right)=0\)
Mà \(\frac{1}{24};\frac{1}{26};\frac{1}{28}\)khác \(0\)
\(\Leftrightarrow x-124=0\Leftrightarrow x=124\)
24 tháng 9 2016
a )
\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{26}-1=0\)
\(\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\left(x-124\right)\left(\frac{1}{26}+\frac{1}{24}+\frac{1}{28}\right)=0\)
\(\Rightarrow x-124=0\Rightarrow x=124\)
12 tháng 7 2015
\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{28}-1=3-1-1-1=0\)
\(\Rightarrow\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\Rightarrow\left(x-124\right)\left(\frac{1}{24}+\frac{1}{26}+\frac{1}{28}\right)=0\)
\(\Rightarrow x-124=0\) ( vì 1/24 + 1/26 + 1/28 khác 0)
=> x = 124
AH
1
TH
0
TN
22 tháng 6 2016
a)4x+4x+3=4160
=>4x(1+43)=4160
=>4x*65=4160
=>4x=64
=>4x=43
=>x=3
b)Bạn xem lại đề vì số hơi lẻ
MM
1
31 tháng 10 2015
A)=>x + 1/2011+ x + 1/2012 - x + 1/2013 - x + 1/2014 =0
<=>(x + 1) . ( 1/2011+ 1/2012-1/2013 - 1/2014) = 0
=>x + 1 = 0 (vì 1/2011+ 1/2012 - 1/2013 - 1/2014 khác 0)
=>x = -1
vậy x = -1
B)x-100/24+x-98/26+x-96/28=3
<=>x - 100/24 - 1 + x - 98/26 - 1 + x - 96/28 =0
<=>x - 124/24 + x - 124/26 + x - 124/28 = 0
<=>(x-124).( 1/24 + 1/26 + 1/28 ) = 0
mà 1/24 + 1/26 +1/28 khác 0
=>x - 124 = 0
<=>x = 124
Ta có:\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)
\(\Rightarrow\)\(\frac{91x-100.91}{91.24}+\frac{84x-84.98}{26.84}+\frac{78x-96.78}{78.28}\)
=\(\frac{91x-9100+84x-8232+78x-7488}{2184}\)
=\(\frac{91x+84x+78x-9100-8232-7488}{2184}\)
=\(\frac{x\left(91+84+78\right)-\left(9100+8232+7488\right)}{2184}\)
=\(\frac{x253-24820}{2184}=3\)
\(\Rightarrow\)x253- 24820 =6552
\(\Rightarrow\)x253= 31372
\(\Rightarrow\)x = 124
\(\frac{x-100}{24}+\frac{x-98}{+26}+\frac{x-96}{28}=3\)
\(=\frac{\left(x-100\right)}{24}+\frac{\left(x-98\right)}{26}+\frac{\left(x-96\right)}{28}-1=0\)
\(\Leftrightarrow\frac{\left(x-100\right)}{24-1}+\frac{\left(x-98\right)}{26-1}+\frac{\left(x-96\right)}{28-1}=0\)
\(\Leftrightarrow\left(x-124\right)\left(\frac{1}{24}+\frac{1}{26}+\frac{1}{28}\right)=0\)
Vì: \(\frac{1}{24}+\frac{1}{26}+\frac{1}{28}\ne0\)
\(\Rightarrow x-124=0\)
\(\Rightarrow x=124-0\)
\(\Rightarrow x=124\)