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\(x=\sqrt[3]{9+4\sqrt{5}}+\sqrt[3]{9-4\sqrt{5}}\)
\(\Rightarrow x^3=9+4\sqrt{5}+9-4\sqrt{5}+3\sqrt[3]{\left(9+4\sqrt[]{5}\right)\left(9-4\sqrt{5}\right)}\left(\sqrt[3]{9+4\sqrt{5}}+\sqrt[3]{9-4\sqrt{5}}\right)\)
\(=18+3\sqrt{81-80}.x=18+3x\)\(\Rightarrow x^3-3x=18\left(1\right)\)
\(y=\sqrt[3]{3+2\sqrt{2}}+\sqrt[3]{3-2\sqrt{2}}\)
\(\Rightarrow y^3=3+2\sqrt{2}+3-2\sqrt{2}+3\sqrt[3]{\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)}\left(\sqrt[3]{3+2\sqrt{2}}+\sqrt[3]{3-2\sqrt{2}}\right)\)
\(=6+3\sqrt[3]{9-8}.y=6+3y\)\(\Rightarrow y^3-3y=6\left(2\right)\)
\(\left(1\right),\left(2\right)\Rightarrow P=x^3+y^3-3\left(x+y\right)+1996=x^3-3x+y^3-3y+1996\)
\(=18+6+1996=2020\)
\(P=\dfrac{2\sqrt{x}+1+\left(1-\sqrt{x}\right)\left(1+\sqrt{x}\right)}{\sqrt{x}\left(\sqrt{x}+1\right)}:\dfrac{\sqrt{x}+2}{\sqrt{x}}\)
\(=\dfrac{2\sqrt{x}+1+1-x}{\sqrt{x}\left(\sqrt{x}+1\right)}.\dfrac{\sqrt{x}}{\sqrt{x}+2}=\dfrac{-x+2\sqrt{x}+2}{\left(\sqrt{x}+1\right)\left(\sqrt{x}+2\right)}=\dfrac{-x+2\sqrt{x}+2}{x+3\sqrt{x}+2}\)
a: 1-1/2=1/2
b: 1-3/10=7/10
c:3-1/3=8/3
d: 4-1/9=35/9
e: 8-2/3=22/3
f: 5-2/5=23/5
a: bằng 1 phần 2
b: bằng 7 phần 10
c: bằng 2 phần 3
d:bằng 35 phần 9
e: bằng 22 phần 3
g: bằng 23 phần 5
chúc bn học tốt
Tổng hai phân số ban đầu là
7/9+1/5=35/45+9/45=44/45
a: \(\dfrac{5}{3}\cdot\dfrac{4}{5}=\dfrac{4}{3}\)
b: \(\dfrac{2}{3}\cdot\dfrac{3}{5}=\dfrac{2}{5}\)
c: \(\dfrac{7}{6}\cdot\dfrac{6}{5}=\dfrac{7}{5}\)
d: \(\dfrac{8}{5}\cdot\dfrac{5}{7}=\dfrac{8}{7}\)
e: \(\dfrac{7}{6}\cdot\dfrac{6}{7}=\dfrac{7}{7}=1\)
g: \(\dfrac{9}{5}\cdot\dfrac{5}{2}=\dfrac{9}{2}\)
h: \(\dfrac{4}{3}\cdot\dfrac{3}{5}=\dfrac{4}{5}\)
\(a,\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{4}{13}\times\dfrac{3}{2}=\left(\dfrac{13}{4}\times\dfrac{4}{3}\right)\times\left(\dfrac{2}{3}\times\dfrac{3}{2}\right)=1\times1=1\)
\(b,\dfrac{75}{100}+\dfrac{18}{21}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{3}{21}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{18}{21}+\dfrac{3}{21}\right)+\left(\dfrac{19}{32}+\dfrac{13}{32}\right)=1+1+1=3\\ c,\dfrac{4}{7}\times\dfrac{5}{6}+\dfrac{4}{7}\times\dfrac{1}{6}=\dfrac{4}{7}\times\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\times1=\dfrac{4}{7}\\ d,\dfrac{3}{5}\times\dfrac{7}{9}-\dfrac{3}{5}\times\dfrac{2}{9}=\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{1}{3}\)
\(e,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\times1=\dfrac{1}{4}\\ f,\dfrac{7}{9}\times\dfrac{8}{5}\times\dfrac{3}{5}=\dfrac{56}{75}\\ g,\dfrac{2}{5}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{3}{5}=\dfrac{3}{4}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\\ h,\dfrac{2006}{2005}\times\dfrac{3}{4}-\dfrac{3}{4}\times\dfrac{1}{2005}=\dfrac{3}{4}\times\left(\dfrac{2006}{2005}-\dfrac{1}{2005}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\)
a: \(=\dfrac{13}{4}\cdot\dfrac{4}{13}\cdot\dfrac{2}{3}\cdot\dfrac{3}{2}=1\cdot1=1\)
b: \(=\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{6}{7}+\dfrac{1}{7}+\dfrac{19}{32}+\dfrac{13}{32}=1+1+1=3\)
c: \(=\dfrac{4}{7}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\)
d: \(=\dfrac{3}{5}\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\cdot\dfrac{5}{9}=\dfrac{1}{3}\)
e: \(=\dfrac{1}{4}\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\)
a: =1/3x7/5=7/15
b: =11/9x1/2=11/18
c: =1/3x3/4=1/4
d: =1/5x4/5=4/25
e: =2/3x1/4=2/12=1/6
f: =1/2x1/3=1/6
g: =1/3x1/2=1/6
it began in the 11th century.
It takes place in a pool.
They are controlled by puppeteers.
They are made of wood.
They are about everyday life in the countryside and about folk tales.
1. it began in the 11th century
2 in the village of the red river delta of north of vietnam
3 puppeteers
4 wood
5 everyday life in the countryside and folk tales