X+5/2013+x+7/2011=x+1/2017+x+2/2016
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20 tháng 5 2022
a: Sửa đề: \(\dfrac{2x-1}{11}+\dfrac{2x-2}{12}+\dfrac{2x-3}{13}=\dfrac{2x+5}{5}+\dfrac{2x+7}{3}+\dfrac{2x+4}{6}\)
\(\Leftrightarrow\dfrac{2x-1}{11}+1+\dfrac{2x-2}{12}+1+\dfrac{2x-3}{13}+1=\dfrac{2x+5}{5}+1+\dfrac{2x+7}{3}+1+\dfrac{2x+4}{6}+1\)
=>2x+10=0
hay x=-5
b: \(\dfrac{x-1}{2016}+\dfrac{x-2}{2015}+\dfrac{x-3}{2014}+\dfrac{x-4}{2013}+\dfrac{x-5}{2012}-5=0\)
\(\Leftrightarrow\left(\dfrac{x-1}{2016}-1\right)+\left(\dfrac{x-2}{2015}-1\right)+\left(\dfrac{x-3}{2014}-1\right)+\left(\dfrac{x-4}{2013}-1\right)+\left(\dfrac{x-5}{2012}-1\right)=0\)
=>x-2017=0
hay x=2017
20 tháng 5 2022
a: Sửa đề: \(\dfrac{2x-1}{11}+\dfrac{2x-2}{12}+\dfrac{2x-3}{13}=\dfrac{2x+5}{5}+\dfrac{2x+7}{3}+\dfrac{2x+4}{6}\)
\(\Leftrightarrow\dfrac{2x-1}{11}+1+\dfrac{2x-2}{12}+1+\dfrac{2x-3}{13}+1=\dfrac{2x+5}{5}+1+\dfrac{2x+7}{3}+1+\dfrac{2x+4}{6}+1\)
=>2x+10=0
hay x=-5
b: \(\dfrac{x-1}{2016}+\dfrac{x-2}{2015}+\dfrac{x-3}{2014}+\dfrac{x-4}{2013}+\dfrac{x-5}{2012}-5=0\)
\(\Leftrightarrow\left(\dfrac{x-1}{2016}-1\right)+\left(\dfrac{x-2}{2015}-1\right)+\left(\dfrac{x-3}{2014}-1\right)+\left(\dfrac{x-4}{2013}-1\right)+\left(\dfrac{x-5}{2012}-1\right)=0\)
=>x-2017=0
hay x=2017
NT
1
28 tháng 1 2018
\(\text{Đầu bài viết khó nhìn thí mồ!! viết lại nhé!!}\)
\(\frac{x+1}{2013}+\frac{x+2}{2012}+\frac{x+3}{2011}=\frac{x-1}{2015}+\frac{x-2}{2016}+\frac{x-3}{2017}\)
\(\Rightarrow\frac{x+1}{2013}+1+\frac{x+2}{2012}+1+\frac{x+3}{2011}+1=\frac{x-1}{2015}+1+\frac{x-2}{2016}+1+\frac{x-3}{2017}+1\)
\(\Leftrightarrow\frac{x+2014}{2013}+\frac{x+2014}{2012}+\frac{x+2014}{2011}-\frac{x+2014}{2015}-\frac{x+2014}{2016}-\frac{x+2014}{2017}=0\)
\(\Leftrightarrow\left(x+2014\right)\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2015}-\frac{1}{2016}-\frac{1}{2017}\right)=0\)
\(\text{Mà }\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2015}-\frac{1}{2016}-\frac{1}{2017}\ne0\)
\(\text{Nên }x+2014=0\Leftrightarrow x=-2014\)
22 tháng 8 2016
D. Tìm x thuộc Z biết
x+(x+1)+(x+2)+....+2016+2017=2017
=> ( x + x + x + ..+ x ) + ( 1 + 2 + 3+...+2016 + 2017 ) = 2017
<=> 2017x + 2035153 = 2017
=> 2017x = -2033136
=> x = -1008
Vậy ...
23 tháng 8 2016
cảm ơn bạn nhưng bạn có biết những câu hỏi còn lại ko
\(\frac{x+5}{2013}+\frac{x+7}{2011}=\frac{x+1}{2017}+\frac{2}{2016}\)
\(\Leftrightarrow\left(\frac{x+5}{2013}+1\right)+\left(\frac{x+7}{2011}+1\right)=\left(\frac{x+1}{2017}+1\right)+\left(\frac{x+2}{2016}+1\right)\)
\(\Leftrightarrow\frac{x+2018}{2013}+\frac{x+2018}{2011}=\frac{x+2018}{2017}+\frac{x+2018}{2016}\)
\(\Leftrightarrow\frac{x+2018}{2013}+\frac{x+2018}{2011}-\frac{x+2018}{2017}-\frac{x+2018}{2016}=0\)
\(\Leftrightarrow\left(x+2018\right)\left(\frac{1}{2013}+\frac{1}{2011}-\frac{1}{2017}-\frac{1}{2016}\right)=0\)
Mà \(\frac{1}{2013}+\frac{1}{2011}-\frac{1}{2017}-\frac{1}{2016}\ne0\)
\(\Leftrightarrow x+2018=0\)
\(\Leftrightarrow x=-2018\)
Vậy ...
\(\frac{x+5}{2013}+\frac{x+7}{2011}=\frac{x+1}{2017}+\frac{2}{2016}\)
\(\Leftrightarrow\left(\frac{x+5}{2013}+1\right)+\left(\frac{x+7}{2011}+1\right)=\left(\frac{x+1}{2017}+1\right)+\left(\frac{x+2}{2016}+1\right)\)
\(\Leftrightarrow\frac{x+2018}{2013}+\frac{x+2018}{2011}=\frac{x+2018}{2017}+\frac{x+2018}{2016}\)
\(\Leftrightarrow\frac{x+2018}{2013}+\frac{x+2018}{2011}-\frac{x+2018}{2017}-\frac{x+2018}{2016}=0\)
\(\Leftrightarrow\left(x+2018\right)\left(\frac{1}{2013}+\frac{1}{2011}-\frac{1}{2017}-\frac{1}{2016}\right)=0\)
Mà \(\frac{1}{2013}+\frac{1}{2011}-\frac{1}{2017}-\frac{1}{2016}\ne0\)
\(\Leftrightarrow x+2018=0\)
\(\Leftrightarrow x=-2018\)
Vậy \(x=-2018\)