* Tính
a) (1/64)^4=(-1/8)^14
b) 7.2x=29+5.28
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\(S=1+2+2^2+2^3+...+2^9\)
Đặt \(2S=2+2^2+2^3+2^4+...+2^{10}\)
\(2S-S=2^{10}-1\) hay \(S=2^{10}-1< 2^{10}\)
\(\Rightarrow\) \(2^{10}=2^2.2^8< 5.2^8\)
Vậy \(S< 5.2^8\)
\(#Tuyết\)
2S=2+2^2+...+2^10
=>S=2^10-1=1023
5*2^8=256*5=1280
=>S<5*2^8
a: \(\dfrac{x^3}{8}=\dfrac{y^3}{64}=\dfrac{z^3}{216}\)
=>\(\left(\dfrac{x}{2}\right)^3=\left(\dfrac{y}{4}\right)^3=\left(\dfrac{z}{6}\right)^3\)
=>\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}\)
=>\(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}\)
Đặt \(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}=k\)
=>x=k; y=2k; z=3k
\(x^2+y^2+z^2=14\)
=>\(k^2+4k^2+9k^2=14\)
=>\(14k^2=14\)
=>\(k^2=1\)
=>k=1 hoặc k=-1
TH1: k=1
=>\(x=k=1;y=2k=2\cdot1=2;z=3k=3\cdot1=3\)
TH2: k=-1
=>\(x=k=-1;y=2k=2\cdot\left(-1\right)=-2;z=3k=3\cdot\left(-1\right)=-3\)
b: \(\dfrac{x^3}{8}=\dfrac{y^3}{27}=\dfrac{z^3}{64}\)
=>\(\left(\dfrac{x}{2}\right)^3=\left(\dfrac{y}{3}\right)^3=\left(\dfrac{z}{4}\right)^3\)
=>\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\)
Đặt \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=k\)
=>x=2k; y=3k; z=4k
\(x^2+2y^2-3z^2=-650\)
=>\(\left(2k\right)^2+2\cdot\left(3k\right)^2-3\cdot\left(4k\right)^2=-650\)
=>\(4k^2+18k^2-3\cdot16k^2=-650\)
=>\(-26\cdot k^2=-650\)
=>\(k^2=25\)
=>\(\left[{}\begin{matrix}k=5\\k=-5\end{matrix}\right.\)
TH1: k=5
=>\(x=2\cdot5=10;y=3\cdot5=15;z=4\cdot5=20\)
TH2: k=-5
=>\(x=2\cdot\left(-5\right)=-10;y=3\cdot\left(-5\right)=-15;z=4\cdot\left(-5\right)=-20\)
a) 19 + (29 - 9*37) - (63*9 - 29*99)
= 19 + 29 - 9*37 - 63*9 + 29*99
= 19 + 29(1 + 99) - 9(37 + 63)
= 19 + 29*100 - 9*100
= 19 + 100(29 - 9)
= 19 + 100*20
= 19 + 2000 = 2019
b) \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)
= \(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}\)
= \(\frac{2^6+2^5+2^4+2^3+2^2+2+1}{2^7}\)
= \(\frac{64+32+16+8+4+2+1}{128}\) = \(\frac{127}{128}\)
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)
\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}=\frac{81}{10}\)
Bài 1:
29.(85-47)+85.(47-29)
=29.38+85.18
=1102+1530
=2632
BÀI 2
a, 15x = -75
x =( -75) : 15
x = -5
Vậy x= -5
b,-5x+8=-27
-5x = -27 - 8
-5x= -35
x =-35 : -5
x = 7
Vậy x = 7
c,3.(17 + x ) = - 42
17 + x = - 42 : 3
17 + x = -14
x = - 14 - 17
x = -31
Vậy x = - 31
d,-10 -( 2x -16) = 0
2x - 16 = 10-0
2x - 16 = 10
2x = 10 +16
2x = 26
x = 26 : 2
x = 13
Vậy x = 13
e,( mik ko bít làm)
f,( tự làm nghen bạn)
a)\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)
\(\frac{1}{2}xA=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)
\(\frac{1}{4}xA=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}+\frac{1}{384}\)
\(\frac{1}{4}xA-\frac{1}{2}xA=\frac{1}{3}-\frac{1}{384}\)
\(\frac{1}{4}xA=\frac{127}{384}\)
\(A=\frac{127}{384}:\frac{1}{4}\)
\(A=\frac{127}{96}\)
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)
\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}=\frac{81}{10}\)
c, 64 * 25 + 35 * 25 + 25
= 64 * 25 + 35 * 25 + 25 * 1
= (64 + 35 + 1) * 25
= 100 * 25
= 2500
a.3 x 25 x 8 + 4 x 37 x 6 + 2 x 38 x 12
=24 x 25 + 24x 37 + 24 x 38
=24 x(25+37+38)
=24 x 100
=2400
b.1+6+11+16+.........+46+51
Khoảng cách dãy số trên là:
6 - 1 = 5
11 - 6 = 5
Vậy khoảng cách dãy số trên là 5
Số số hạng của dãy số trên là:
(51 - 1) / 5 + 1 = 11(số)
Tổng dãy số trên là:
(51+1) x 11 / 2 = 286
Đ/s:286
c.29 x 87 - 29 x 23 + 64 + 71
=29 x (87 - 23) +64 + 71
=29 x 64 + 64 +71
=64 x 29 + 64 x 1 + 71
=64 x (29+1) + 71
=64 x 30 + 71
=1920 + 71
= 1991