Tính
7/12 - 2/7 + 1/12
mih đag cần gấp
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Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
\(\dfrac{7}{12}-\dfrac{1}{6}:\dfrac{2}{5}=\dfrac{7}{12}-\dfrac{5}{12}=\dfrac{2}{12}=\dfrac{1}{6}\)
\(2\times\dfrac{2}{3}+1=\dfrac{4}{3}+1=\dfrac{4}{3}+\dfrac{3}{3}=\dfrac{7}{3}\)
7/12 - 1/6 : 2/5 = 7/12 - 5/12 = 2/12 = 1/6
2 x 2/3 + 1 = 4/3 + 1 = 7/3
1: \(\dfrac{-7}{4}\cdot\dfrac{2}{9}=\dfrac{-14}{36}=\dfrac{-7}{18}\)
2: \(=\dfrac{12}{13}\cdot\dfrac{26}{5}=\dfrac{24}{5}\)
3: \(=\dfrac{20}{11}\cdot\dfrac{55}{21}=\dfrac{100}{21}\)
4: \(=\dfrac{-40}{240}=\dfrac{-1}{6}\)
\(\dfrac{x}{15}\)+\(\dfrac{x}{12}\)=4/1+1/2=9/2
=>x(\(\dfrac{1}{15}\)+\(\dfrac{1}{12}\))=9/2
=>x\(\cdot\)\(\dfrac{3}{20}\)=9/2
=>x=9/2:3/20=30
Vậy x=30
\(\dfrac{x}{15}+\dfrac{x}{12}=\dfrac{9}{2}\Rightarrow\left(\dfrac{1}{15}+\dfrac{1}{12}\right)x=\dfrac{9}{2}\)
\(\Rightarrow\left(\dfrac{12+18}{180}\right)x=\dfrac{9}{2}\Rightarrow\dfrac{30}{180}x=\dfrac{9}{2}\Rightarrow\dfrac{1}{6}x=\dfrac{9}{2}\Rightarrow x=\dfrac{9}{2}.6=27\)
12 : {390 : [500 - (125 + 35 . 7)]}
= 12 : {390 : [500 - (125 + 245)]}
= 12 : [390 : (500 - 370)]
= 12 : (390 : 130)
= 12 : 3
= 4
12 : { 390 : [ 500 - ( 125 + 35. 7 ) ] }
= 12 : { 390 : [ 500 - ( 125 + 245 ) ] }
= 12 : { 390 : [ 500 - 370 ] }
= 12 : { 390 : 130 }
= 12 : 3
= 4
\(\dfrac{4}{7}\times X=\dfrac{1}{2}\\ X=\dfrac{1}{2}:\dfrac{4}{7}=\dfrac{1}{2}\times\dfrac{7}{4}=\dfrac{7}{8}\)
a) 100 + (+430) + 2145+ (-530)
= 100+ 430 + 2145 - 530
= 530 - 530 +2145
= 0 + 2145 = 2145
b) (-12).15 = -10.15 -2.15 = -150 - 30 = -180
c) (+12).13 + 13.(-22)
= 13. (12 - 22)
= 13. (-10)
= -130
d) {[14 : (-2)] + 7} : 2020
= { - 7 + 7} : 2020
= 0 : 2020
=0
Học tốt
1) = \(\frac{3}{5}\)
2) =\(\frac{6}{7}\)
3)\(\frac{9}{13}\)
4)\(\frac{4}{13}\)
Bài 1:
\(f\left(x\right)=-x^{15}+8x^{14}-8x^{13}+...-8x-5\)
Ta xét \(x=7\Leftrightarrow x+1=8\)
Khi đó :
\(f\left(7\right)=-x^{15}+x^{14}\left(x+1\right)-x^{13}\left(x+1\right)+...-x\left(x+1\right)-5\)
\(f\left(7\right)=-x^{15}+x^{15}+x^{14}-x^{14}-x^{13}+...-x^2-x-5\)
\(f\left(7\right)=-x-5\)
\(f\left(7\right)=-7-5\)
\(f\left(7\right)=-12\)
Vậy...
\(\frac{7}{12}-\frac{2}{7}+\frac{1}{12}=\left(\frac{7}{12}+\frac{1}{12}\right)-\frac{2}{7}=\frac{2}{3}-\frac{2}{7}=\frac{14}{21}-\frac{6}{21}=\frac{8}{21}\)
7/12-2/7+1/12=8/21