(1/4) mũ 3 + -3/4.| x - 5 | = -9/2 làm thế nào ạ
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a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)
\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)
\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)
\(=\frac{-60}{45}=\frac{-4}{3}\)
b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)
\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)
\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)
\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)
=\(=\frac{10}{6}=\frac{5}{3}\)
b)\(3.4^2-2.3=3.\left(4^2-3\right)\)
\(=3.13\)
\(=39\)
Học tốt nha!!!
\(\frac{1}{9}.3^4.3^x=3^7\)
\(\Leftrightarrow3^x=3^7:\frac{1}{9}:3^4=243\)
\(\Leftrightarrow3^x=3^5\)
\(\Leftrightarrow x=5\)
a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
\(\left(\frac{1}{4}\right)^3+\frac{-3}{4}.|x-5|=\frac{-9}{2}\)
\(\Rightarrow\frac{1}{64}+\frac{-3}{4}.|x-5|=\frac{-9}{2}\)
\(\Rightarrow\frac{-3}{4}.|x-5|=\frac{-9}{2}-\frac{1}{64}\)
\(\Rightarrow\frac{-3}{4}.|x-5|=\frac{-289}{64}\)
\(\Rightarrow|x-5|=\frac{-289}{64}:\frac{-3}{4}\)
\(\Rightarrow|x-5|=\frac{289}{48}\)
\(\Rightarrow\orbr{\begin{cases}x-5=\frac{289}{48}\\x-5=\frac{-289}{48}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{529}{48}\\x=\frac{-49}{48}\end{cases}}\)
Vậy \(x=\frac{529}{48}\) hoặc \(x=\frac{-49}{48}\)