\(\frac{9.11+32.9}{23.15+12.23}\)
\(\frac{12.13+24.26+36.39}{24.26+48.52+72.78}\)
rút gọn phân số
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a) \(9.11+32.9=9.\left(11+32\right)=9.43=387\)
b) \(23.25+12.23=23.\left(25+12\right)=23.37=851\)
c) \(12.13+24.26+36.39=12.13+12.2.13.2+12.3.13.3\)
\(=12.13+2^2\left(12.13\right)+3^2\left(12.13\right)\)
\(=12.13.\left(1+2^2+3^2\right)=12.13.14=2184\)
d) Câu này tương tự câu trên nha.
Đặt tử số là A , mẫu số là B
Ta có : B = 24 . 26 + 48 . 52 + 72 . 78
= ( 12 . 2 ) . ( 13 . 2 ) + ( 24 . 2 ) . ( 26 . 2 ) + ( 36 . 2 ) . ( 39 . 2 )
= ( 12 .13 ) . ( 2. 2 ) + ( 24 . 26 ) . ( 2 . 2 ) + ( 36 . 39 ) . ( 2 . 2 )
= ( 12 . 13 ) . 4 + ( 24 . 26 ) . 4 + ( 36 . 39 ) . 4
= 4 . ( 12 . 13 + 24 . 26 + 36 . 39 )
= 4 . A ( A là tử số )
lại có : A/B = A/4A
= 1/4
Chúc học giỏi
a)
\(\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20}\)
\(=\frac{1\cdot2\cdot\left(1+2\cdot2+3\cdot3+4\cdot4+5\cdot5\right)}{3\cdot4\cdot\left(1+2\cdot2+3\cdot3+4\cdot4+5\cdot5\right)}\)
\(=\frac{1\cdot2}{3\cdot4}=\frac{1}{6}\)
b) \(\frac{12\cdot13+24\cdot26+36\cdot39}{24\cdot26+48\cdot52+72\cdot78}\)
\(=\frac{12\cdot13\cdot\left(1+2\cdot2+3\cdot3\right)}{24\cdot26\cdot\left(1+2\cdot2+3\cdot3\right)}\)
\(=\frac{12\cdot13}{24\cdot26}=\frac{1}{4}\)
\(\frac{2\cdot3+4\cdot6+14\cdot21}{3\cdot5+6\cdot10+21\cdot35}=\frac{2\cdot3\cdot\left(1+2\cdot2+7\cdot7\right)}{3\cdot5\cdot\left(1+2\cdot2+7\cdot7\right)}=\frac{2\cdot3}{3\cdot5}=\frac{2}{5}\)
\(\frac{9.11+32.9}{23.15+12.23}=\frac{3^2.11+32.3^2}{23.3.5+12.23}\)
\(=\frac{3^2.\left(11+32\right)}{23.\left(15+12\right)}=\frac{3^2.43}{23.27}\)
\(=\frac{3^2.43}{23.3^3}=\frac{43}{23.3}=\frac{43}{69}\)
\(\frac{24-12.13}{12+4.9}=\frac{24-156}{12+36}=\frac{-132}{48}=\frac{-11}{4}\)
Rút gọn phân số:
\(\frac{24-12.13}{12+4.9}=\frac{24-4.3.13}{12+4.9}=\frac{24-3.13}{12+9}=\frac{24-3.13}{12+3.3}=\frac{24-13}{12+3}=\frac{11}{14}\)
Sai thì thôi nhé!
\(\frac{24-12.13}{12+4.9}\)=\(\frac{24-156}{12+36}\)=\(\frac{-132}{48}\)=-\(\frac{11}{4}\)
a, \(\frac{13.2-13.3}{1-27}\)=\(\frac{13.\left(2-3\right)}{-26}\)=\(\frac{13.\left(-1\right)}{-26}\)=\(\frac{-13}{-26}\)=\(\frac{1}{2}\)
b,\(\frac{15.\left(-3\right)+23.15}{-5+20}\)=\(\frac{15.[\left(-3\right)+23]}{15}\)=\(\frac{15.20}{15}\)=\(\frac{300}{15}\)=20