Tính: \(\frac{1}{1+\frac{2}{3+\frac{4}{5+\frac{6}{7}}}}+\frac{1}{1+\frac{1}{2+\frac{3}{4+\frac{4}{5}}}}\)
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\(\frac{1}{2}-\frac{2}{3}+\frac{3}{4}-\frac{4}{5}-\frac{6}{7}-\frac{5}{6}+\frac{4}{5}-\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\)
\(=\left(\frac{1}{2}-\frac{1}{2}\right)-\left(\frac{2}{3}-\frac{2}{3}\right)+\left(\frac{3}{4}-\frac{3}{4}\right)-\left(\frac{4}{5}-\frac{4}{5}\right)-\left(\frac{6}{7}+\frac{5}{6}\right)\)
\(=-\frac{71}{42}\)
\(=\frac{5\left(\frac{1}{3}+\frac{1}{8}-\frac{1}{7}\right)}{-4\left(\frac{1}{3}+\frac{1}{8}-\frac{1}{7}\right)}:\frac{2\left(\frac{1}{3}-\frac{1}{12}+\frac{3}{7}\right)}{ }\)
MÃu thứ hai sao ý
c.\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\frac{25}{108}.\frac{5751}{25}+\frac{187}{4}}{\frac{100}{21}:-\frac{41}{21}}\)
\(\frac{\frac{213}{4}+\frac{187}{4}}{-\frac{100}{41}}\)
\(\frac{100}{-\frac{100}{41}}=-41\)
a. \(\frac{4}{9}:-\frac{1}{7}+6\frac{5}{9}:-\frac{1}{7}\)
\(\left(\frac{4}{9}+6\frac{5}{9}\right):-\frac{1}{7}\)
\(7:-\frac{1}{7}=-49\)
Bài này được cái rối mắt thôi :')))
\(\frac{1}{1+\frac{2}{3+\frac{4}{5+\frac{6}{7}}}}+\frac{1}{1+\frac{1}{2+\frac{3}{4+\frac{4}{5}}}}=\frac{1}{1+\frac{2}{3+\frac{4}{\frac{41}{7}}}}+\frac{1}{1+\frac{1}{2+\frac{3}{\frac{24}{5}}}}\)
\(=\frac{1}{1+\frac{2}{3+\frac{28}{41}}}+\frac{1}{1+\frac{1}{2+\frac{5}{8}}}=\frac{1}{1+\frac{2}{\frac{151}{41}}}+\frac{1}{1+\frac{1}{\frac{21}{8}}}\)
\(=\frac{1}{1+\frac{8}{151}}+\frac{1}{1+\frac{8}{21}}=\frac{1}{\frac{159}{151}}+\frac{1}{\frac{29}{21}}=\frac{151}{159}+\frac{21}{29}\)