Question

[Phương Nguyễn]

Bài 1:Thực hiện phép tính.

1) \(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\) ; 2)\(\dfrac{15^3+5\cdot15^2-5^3}{18^2+6\cdot18^2-6^3}\)

Bài 2:Tìm x, biết:

1)\(^{\left(5x+1\right)^2}\)=\(\dfrac{36}{49}\) ; 2) \(2^{x-1}=16\) ; 3)\(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\) ; 4)\(\dfrac{-1}{2}+\dfrac{5}{x+3}=\dfrac{-5}{6}\)

5)\(\dfrac{37-x}{x+13}=\dfrac{3}{7}\) ; 6)\(\dfrac{1}{12}:\dfrac{4}{21}=3\dfrac{1}{2}:\left(3x-2\right)\) ; 7) \(^{2^{2x+1}+4^{x+3}=264}\) ; 8) \(\dfrac{x+7}{-20}=\dfrac{-5}{x+7}\)

9) \(\dfrac{x}{8}=\dfrac{x}{x^3}\) ; 10) \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)

Mọi người giúp mình với,làm ơn !!!!!

Answer 1

[Nguyễn Lê Phước Thịnh]

Bài 2:

1: =>5x+1=6/7 hoặc 5x+1=-6/7

=>5x=-1/7 hoặc 5x=-13/7

=>x=-1/35 hoặc x=-13/35

2: =>x-1=4

=>x=5

3: =>3x-1=3

=>3x=4

=>x=4/3

4: \(\Leftrightarrow\dfrac{5}{x+3}=\dfrac{-5}{6}+\dfrac{1}{2}=\dfrac{-5+3}{6}=\dfrac{-2}{6}=\dfrac{-1}{3}\)

=>x+3=-15

=>x=-18

7: \(\Leftrightarrow2^{2x+1}+2^{2x+6}=264\)

=>2^2x+1*(1+2^5)=264

=>2^2x+1=8

=>2x+1=3

=>x=1

9: =>x^4=8x

=>x^4-8x=0

=>x=2