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\(\frac{1}{2}+\frac{5}{6}+...+\frac{89}{90}+\frac{109}{110}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+...+1-\frac{1}{90}+1-\frac{1}{110}\)
\(=\left(1+1+...+1\right)-\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{90}+\frac{1}{110}\right)\)(có 10 số 1)
\(=10+\left(\frac{1}{1x2}+\frac{1}{2x3}+...+\frac{1}{9x10}+\frac{1}{10x11}\right)\)
\(=10+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=10+\left(1-\frac{1}{11}\right)\)
\(=10+\frac{10}{11}=10\frac{10}{11}\)
1/2+5/6+...+89/90+109
=(1-1/2)+(1-1/6)+...+(1-1/90)+109
=(1+1+....+1)- (1/2+1/6+...+1/90)+109 (có 9 số hạng 1)
= 9- (1/1*2+1/2*3+...+1/9*10)+109
= 9- (1-1/2+1/2-1/3+...+1/9-1/10)+109
= 9- (1-1/10) +109
=9-9/10+109
=90/10-9/10+109
=81/10+109
=1171/10
a / ( 1/2 + 1/10 + 3/5 ) = 425
a / ( 6/5 ) = 325
a = 325 * 6/5 = 390
x / ( 11/7 + 6/7 + 8/14 + 29 ) = 35
x / 32 = 35
x = 35 * 32 = 1120
câu thứ 3 nghĩa là sao
S=2/6+2/12+2/20+...+2/90
S=2/2.3+2/3.4+...+2/9.10
S=2(1/2.3+...+1/9.10)
S=2(1/2-1/3+...+1/9-1/10)
S=2.2/5
S=4/5
\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{90}\)
\(=\frac{2}{2x3}+\frac{2}{3x4}+\frac{2}{4x5}+...+\frac{2}{9x10}\)
\(=\left(\frac{2}{2x3}+\frac{2}{3x4}+\frac{2}{4x5}+...+\frac{2}{9x10}\right):2x2\)
\(=\left(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{9x10}\right)x2\)
\(=\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)x2\)
\(=\left(\frac{1}{2}-\frac{1}{10}\right)x2\)
\(=\frac{4}{5}x2\)
\(=\frac{8}{5}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}\)
\(=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{9x10}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
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