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1: \(x^2-xy+x-y\)

\(=x\left(x-y\right)+\left(x-y\right)\)

=(x-y)(x+1)

2: \(xy-2x-y^2+2y\)

=x(y-2)-y(y-2)

=(y-2)(x-y)

3: \(x^2+4x-y^2+4\)

\(=\left(x^2+4x+4\right)-y^2\)

\(=\left(x+2\right)^2-y^2=\left(x+2+y\right)\left(x+2-y\right)\)

4: \(x^2+4x-y^2+4\)

\(=\left(x^2+4x+4\right)-y^2\)

\(=\left(x+2\right)^2-y^2=\left(x+2+y\right)\left(x+2-y\right)\)

5: \(x^2-2xy+y^2-4\)

\(=\left(x^2-2xy+y^2\right)-4\)

\(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)

6: \(xz+yz-5x-5y\)

=z(x+y)-5(x+y)

=(x+y)(z-5)

7: \(x^2-2xy+y^2-x+y\)

\(=\left(x-y\right)^2-\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y-1\right)\)

8:  \(x^2-y^2-2x-2y\)

\(=\left(x-y\right)\left(x+y\right)-2\left(x+y\right)\)

=(x+y)(x-y-2)

9: \(x^2-1-2xy+2y\)

\(=\left(x-1\right)\left(x+1\right)-2y\left(x-1\right)\)

\(=\left(x-1\right)\left(x+1-2y\right)\)

10: \(x^2-3x+xy-3y\)

\(=x\left(x-3\right)+y\left(x-3\right)\)

\(=\left(x-3\right)\left(x+y\right)\)

23 tháng 8 2024

8) x² - y² - 2x + 2y

= (x² - y²) - (2x - 2y)

= (x - y)(x + y) - 2(x - y)

= (x - y)(x + y - 2)

12 tháng 7 2019

a,\(xy+3x-7y-21\)

\(=x\left(y+3\right)-7\left(y+3\right)\)

\(=\left(y+3\right)\left(x-7\right)\)

12 tháng 7 2019

\(b,2xy-15-6x+5y\)

\(=\left(2xy-6x\right)+\left(-15+5y\right)\)

\(=2x\left(y-3\right)-5\left(3-y\right)\)

\(=2x\left(y-3\right)+5\left(y-3\right)\)

\(=\left(y-3\right)\left(2x+5\right)\)

2: \(=3\left(x-2y\right)+y\left(x-2y\right)=\left(x-2y\right)\left(y+3\right)\)

3: \(=x^2+2x+1-y^2\)

\(=\left(x+1\right)^2-y^2\)

\(=\left(x+1+y\right)\left(x+1-y\right)\)

4: \(x^2+2x+1-16y^2\)

\(=\left(x+1\right)^2-16y^2\)

\(=\left(x+1+4y\right)\left(x+1-4y\right)\)

5: \(x^2-y^2+5x+5y\)

\(=\left(x-y\right)\left(x+y\right)+5\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y+5\right)\)

6: \(=25-\left(x^2-2xy+y^2\right)\)

\(=25-\left(x-y\right)^2\)

\(=\left(5-x+y\right)\left(5+x-y\right)\)

12 tháng 9 2020

Áp dụng HĐT a2 - b2 = ( a - b )( a + b )

và tính chất an.bn = ( a.b )n ( với n ∈ N* )

a) ( 3x + 1 )2 - ( x + 1 )2

= [ ( 3x + 1 ) - ( x + 1 ) ][ ( 3x + 1 ) + ( x + 1 ) ]

= ( 3x + 1 - x - 1 )( 3x + 1 + x + 1 )

= 2x( 4x + 2 )

= 2x.2( 2x + 1 )

= 4x( 2x + 1 )

b) ( x + y )2 - ( x - y )2

= [ ( x + y ) - ( x - y ) ][ ( x + y ) + ( x - y ) ]

= ( x + y - x + y )( x + y + x - y )

= 2y.2x = 4xy

c) ( 2xy + 1 )2 - ( 2x + y )2

= [ ( 2xy + 1 ) - ( 2x + y ) ][ ( 2xy + 1 ) + ( 2x + y ) ]

= ( 2xy + 1 - 2x - y )( 2xy + 1 + 2x + y )

= [ ( 2xy - 2x ) - ( y - 1 ) ][ ( 2xy + 2x ) + ( y + 1 ) ]

= [ 2x( y - 1 ) - ( y - 1 ) ][ 2x( y + 1 ) + ( y + 1 ) ]

= ( y - 1 )( 2x - 1 )9 y + 1 )( 2x + 1 )

d) 9( x - y )2 - 4( x + y )2

= 32( x - y )2 - 22( x + y )2 

= [ 3( x - y ) ]2 - [ 2( x + y ) ]2

= ( 3x - 3y )2 - ( 2x + 2y )2

= [ ( 3x - 3y ) - ( 2x + 2y ) ][ ( 3x - 3y ) + ( 2x + 2y ) ]

= ( 3x - 3y - 2x - 2y )( 3x - 3y + 2x + 2y ) 

= ( x - 5y )( 5x - y )

e) ( 3x - 2y )2 - ( 2x - 3y )2

= [ ( 3x - 2y ) - ( 2x - 3y ) ][ ( 3x - 2y ) + ( 2x - 3y ) ]

= ( 3x - 2y - 2x + 3y )( 3x - 2y + 2x - 3y )

= ( x + y )( 5x - 5y )

= ( x + y )5( x - y )

f) ( 4x2 - 4x + 1 ) - ( x + 1 )2

= ( 2x - 1 )2 - ( x + 1 )2

= [ ( 2x - 1 ) - ( x + 1 ) ][ ( 2x - 1 ) + ( x + 1 ) ]

= ( 2x - 1 - x - 1 )( 2x - 1 + x + 1 )

= 3x( x - 2 )

1 tháng 7 2018

\(a)\) \(x^2-2x-4y^2-4y\)

\(=\)\(\left(x^2-2x+1\right)-\left(4y^2+4y+1\right)\)

\(=\)\(\left(x-1\right)^2-\left(2y+1\right)^2\)

\(=\)\(\left(x-1-2y-1\right)\left(x-1+2y+1\right)\)

\(=\)\(\left(x-2y-2\right)\left(x+2y\right)\)

\(=\)\(2\left(x-y\right)\left(x+2y\right)\)

Chúc bạn học tốt ~ 

a) Ta có x- 2x - 4y- 4y

= x2 - 2x + 1 - 4y2 - 4y - 1 

= (x - 1)2 - (4y2 + 4y + 1)

=  (x - 1)2 - (2y + 1)2

= (x - 1 - 2y  - 1)(x - 1 + 2y + 1)

= (x  - 2y - 1)(x + 2y)

12 tháng 8 2015

a) x^4 - x^3 - x + 1 

= x^3 ( x - 1 ) - ( x- 1 )

= ( x^3 - 1 )(x - 1)

= ( x- 1 )^2 (x^2 + x +  1 )

 

12 tháng 8 2015

a)x4-x3-x+1

=x3(x-1)-(x-1)

=(x-1)(x3-1)

=(x-1)(x-1)(x2+x+1)

=(x-1)2(x2+x+1)

b)5x2-4x+20xy-8y

(sai đề)

 

3 tháng 10 2017

đề bài đâu

ucche

3 tháng 10 2017

cô hk ghi nha bn

sorry nha

14 tháng 8 2015

a/ \(=3y^2-6y-2x+1\)

b/ \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

c/ \(=\left(2-x\right)^3\)

d/ \(=xy^2+x^2y+3xy+x^2y+x^3+3x^2-3xy-3x^2-9x\)

\(=xy\left(y+x+3\right)+x^2\left(y+x+3\right)-3x\left(y+x+3\right)\)

\(=\left(xy+x^2-3x\right)\left(y+x+3\right)=x\left(y+x-3\right)\left(y+x+3\right)\)

e/ \(=xy-x^2+2x-y^2+xy-2y\)

\(=x\left(y-x+2\right)-y\left(y-x+2\right)=\left(x-y\right)\left(y-x+2\right)\)

14 tháng 8 2015

a) =(2x+3y-1)2

b)=-(x-1)3

c)=-(x3-6x2+12x-8)=-(x-2)3

d)x3 + 2x2y + xy2 – 9x

    = x(x2 + 2xy + y2 -9)

    = x[(x2 + 2xy + y2) - 32]

    = x[(x + y)2 - 32]

    = x (x + y – 3)(x + y + 3)

e) 2x-2y-x2+2xy-y2=2(x-y)-(x-y)2=(x-y)(2-x+y)