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\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(=\frac{2.\left(5.2-3^2\right)}{5.3-7.2}=\frac{2.\left(5.2-3^2\right)}{15-14}=2.\left(5.2-3^2\right)\)
5.415.99−4.320.895.29.619−7.229.276
=5.(22)15.(32)9−22.320.(23)95.29.(2.3)19−7.229.(33)6
=5.230.318−229.3205.228.319−7.229.318
=229.318.(5.2−32)228.318.(5.3−7.2)
=2.(5.2−32)5.3−7.2 =2.(5.2−32)15−14 =2.(5.2−32)
\(\dfrac{5.4^{15}.9^9+4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}=\dfrac{5.2^{30}.3^{18}+2^2.3^{20}.2^{27}}{5.2^{10}.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
=\(\dfrac{5.2^{30}.3^{18}+2^{29}.3^{20}}{5.2^{29}.3^{19}-7.2^{29}.3^{18}}=\dfrac{2^{29}.3^{18}\left(5.2+3^2\right)}{2^{29}.3^{18}\left(5.3-7\right)}\)
=\(\dfrac{10+9}{15-7}=\dfrac{19}{8}\)
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-3^{20}.2^{29}}{5.2^{29}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-9\right)}{2^{29}.3^{18}.\left(5.3-7\right)}=1\)
5.415.99-4.320.89 5.230.318-22.320.227 5.230.318-22.320.227 5.230.318-22.227.320
------------------------ = -------------------------------------- = -------------------------------------- =--------------------------------------
5.210.619-7.229.276 5.210.(2.3)19-7.229.318 5.210.219.319-7.229.318 5.229.319-7.229.318
= 5.230.318-229.320
--------------------------------------
5.229.319-7.229.318
làm nốt nha!!
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5\cdot2^{10}\cdot6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)
\(=\frac{2.\left(10-9\right)}{15-14}\)
\(=2\)
Vậy BT trên có giá trị là: 2
