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a)\(\frac{8}{3}\)
b)\(\frac{1}{5}=0,2\)
c)\(\frac{17}{135}\)
d)\(\frac{2}{3}\)
e)\(\frac{5}{2}=2,5\)
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\(\frac{22}{5}x\frac{25}{18}=\frac{550}{90}=\frac{55}{9}\)
\(\frac{9}{11}:2\frac{5}{2}x2\frac{3}{4}=\frac{9}{11}:\frac{9}{2}x\frac{11}{4}=\frac{9}{11}x\frac{2}{9}x\frac{11}{4}=\frac{1}{2}\)
\(10:\frac{35}{24}:\frac{36}{7}=10x\frac{24}{35}x\frac{7}{26}=\frac{10}{1}x\frac{24}{35}x\frac{7}{26}=\frac{24}{13}\)
10,77 x 9,8 + 5,23 x 9,8
= (10,77 + 5,23) x 9,8 = 16 x 9,8 = 156,8
1,26 x 3,6 : 0,28 - 6,2 = 4,536 : 0,28 - 6,2=
16,2 - 6,2 = 10
20/11 x 33/23 x 69/180 =
1/1 x 3/1 x 3/9 =
3/1 x 1/3 = 1
(Câu cuối trong fx không có phần gạch giữa {S} nên mình ghi tạm ngoài này nha bạn!)
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\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
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\(a,5\frac{1}{4}+3,25-50\%+y=15,25\)
\(\Leftrightarrow5,25+3,25-\frac{50}{100}+y=15,25\)
\(\Leftrightarrow5,25+3,25-0,5+y=15,25\)
\(\Leftrightarrow8+y=15,25\)
\(\Leftrightarrow y=15,25-8=7,25\)
\(b,(y-3):2=2010\)
\(\Leftrightarrow y-3=4020\)
\(\Leftrightarrow y=4023\)
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Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
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`a)1/7xx2/7+1/7xx5/7+6/7`
`=1/7xx(2/7+5/7)+6/7`
`=1/7xx1+6/7`
`=1/7+6/7=1`
`b)6/11xx4/9+6/11xx7/9-6/11xx2/9`
`=6/11xx(4/9+7/9-2/9)`
`=6/11xx9/9`
`=6/11`
Sorry nãy ghi thiếu.
`c)4/25xx5/8xx25/4xx24`
`=(4xx5xx25xx24)/(25xx8xx4)`
`=(4xx5xx24)/(4xx8)`
`=(5xx24)/8`
`=5xx3=15`
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\(\dfrac{11}{49}\times\dfrac{9}{1}\times\dfrac{7}{33}=\dfrac{11\times9\times7}{7\times7\times1\times11\times3}=\dfrac{9}{21}=\dfrac{3}{7}\)
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a) \(2g=120p->\left(120+22\right)\text{x}4=568\left(ph\text{út}\right)\)
b) \(25g=1500p->\left(1500+30\right):5=306\left(ph\text{ú}t\right)\)
c) \(11g=660p;2g=120p->\left(660+45\right)+\left(120+33\right)=858\left(ph\text{ú}t\right)\)
d) \(7g=420p;5g=300p\) \(->\left(420+45\right)+\left(300+23\right)=788\left(ph\text{ú}t\right)\)
\(\dfrac{11}{25}\times9\times\dfrac{5}{33}=\dfrac{99}{25}\times\dfrac{5}{33}=\dfrac{3}{5}\)
cảm ơn bn nhìu =)