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\(\dfrac{6}{21}-\dfrac{-12}{44}+\dfrac{10}{12}-\dfrac{-1}{4}-\dfrac{18}{33}\)
\(=\dfrac{6}{21}+\dfrac{12}{44}+\dfrac{10}{12}+\dfrac{1}{4}-\dfrac{18}{33}\)
\(=\dfrac{1013}{924}\)
\(\dfrac{6}{21}-\dfrac{-12}{44}+\dfrac{10}{44}-\dfrac{1}{-4}-\dfrac{18}{33}\)
\(=\dfrac{2}{7}+\dfrac{3}{11}+\dfrac{5}{7}+\dfrac{1}{4}-\dfrac{9}{11}\)
\(=\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{11}-\dfrac{9}{11}\right)+\dfrac{1}{4}\)
\(=1+-\dfrac{6}{11}+\dfrac{1}{4}\)
\(=\dfrac{5}{11}+\dfrac{1}{4}\)
\(=\dfrac{31}{44}\)
Ta có:
\(12=2^2\cdot3\)
\(18=2\cdot3^2\)
\(75=3\cdot5^2\)
\(\Rightarrow BCNN\left(12,18,75\right)=2^2\cdot3^2\cdot5^2=900\)
\(\Rightarrow\)Phân số cần tìm là \(\frac{900}{45}\)
`6/21-(-12/44)+10/14-(1/(-4))-18/33`
`=2/7+12/44+5/7-((-1)/4)-6/11`
`=2/7+3/11+5/7+1/4-6/11`
`=(3/11-6/11)+(2/7+5/7)+1/4`
`=-3/11+7/7+1/4`
`=43/44`
= \(\dfrac{2}{7}\) - \(\dfrac{-3}{11}\)+\(\dfrac{5}{7}\)-\(\dfrac{-1}{4}\)- \(\dfrac{6}{11}\)
= (\(\dfrac{2}{7}\)+\(\dfrac{5}{7}\)) - ( \(\dfrac{-3}{11}\)+ \(\dfrac{6}{11}\)) - \(\dfrac{-1}{4}\)
= 1 - \(\dfrac{3}{11}\)-\(\dfrac{-1}{4}\)
= \(\dfrac{44}{44}\)-\(\dfrac{12}{44}\)-\(\dfrac{-11}{44}\)
= \(\dfrac{43}{44}\)
33/18
45/44