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5/9 <1 ; 11/7 >1 ; 17/18<1 ; 1> 5/9 ; 1<11/7 ; 1>17/18
tick cho mình nhé
c1 :ta thấy : 5 / 6 bé hơn 1
6 / 5lon hơn 1 nên 6/5 lớn hơn 5/6
c2 5/6=5*5/6*5=25/30
6/5=6*6/5*6=36/30 ma 25 < 36 nen 5/6 < 6/5
a,17/23 + (1 - 17/23)
= 17/23 + 6/23
= 23/23 = 1
b,17/12 + 9/7 - (2/7 + 5 /12)
= (17/12 - 5/12) + (9/7 + 2/7)
= 1+1 = 2
c, 7/13 - ( 4/7 -6/13 )
= 7/13 - 4/7+ 6/13
= (7/13 + 6/13) -4/7
= 13/13 -4/7
= 1 -4/7 = 3/7
hok tốt✍️ ✍️
a) 17/23+(1-17/23)
=17/23+1-17/23
=1
b)17/12+9/7-(2/7+5/12)
=17/12+9/7-2/7-5/12
=1+1
=2
c)
7/13-(4/7-6/13)
=7/13-4/7+6/13
=1-4/7
=3/7
a) 17/23 + (1 - 17/23)
= 17/23 + 1 - 17/23
= (17/23 - 17/23) + 1
= 0 + 1 = 1
b) 17/12 + 9/7 - (2/7 + 5/12)
= 17/12 + 9/7 - 2/7 - 5/12
= (17/12 - 5/12) + (9/7 - 2/7)
= 1 + 1 = 2
c) 7/13 - (4/7 - 6/13)
= 7/13 - 4/7 + 6/13
= (6/13 + 6/12) - 4/7
= 1 - 4/7 = 3/7
d) 7/18 + 3/16 + 11/18 + 13/16
= (7/18 + 11/18) + (3/16 + 13/16)
= 1 + 1 = 1
d) sửa 7/18 + 3/16 + 11/18 + 13/16
= (7/18 + 11/18) + (3/16 + 13/16)
= 1 + 1
= 2
1)
14/32=7/16
2)
3/4=3/4 5/7<6/7
8/5>8/15 13/8>17/18
7/9=7/9 3/5>4/7
3)
a,9/8;25/18;9/3
b,14/16;13/18;7/8,35/40
c,không có
\(A=290-18\times1+567:17\)
\(A=290-18+\frac{567}{17}\)
\(A=272+\frac{567}{17}\)
\(A=\frac{4624}{17}+\frac{567}{17}\)
\(A=\frac{5191}{17}\).
\(B=\frac{1}{7}\times3\frac{1}{11}-\frac{1}{7}\times\frac{9}{11}-\frac{1}{7}\)
\(B=\frac{1}{7}\times\frac{34}{11}-\frac{1}{7}\times\frac{9}{11}-\frac{1}{7}\)
\(B=\left(\frac{34}{11}-\frac{9}{11}-1\right)\times\frac{1}{7}\)
\(B=\left(\frac{25}{11}-1\right)\times\frac{1}{7}\)
\(B=\frac{14}{11}\times\frac{1}{7}\)
\(B=\frac{87}{77}\)
Chúc bạn hok tốt !
5/9 < 1
1 < 9/5
11/7 > 1
1 > 7/11
17/18 < 1
18/18 = 1
tk nha
5/9 <1
11/7 <1
17/18 <1
1< 9/5\
1>7/11
18/18 =1
Tích nhá bạn