![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\Leftrightarrow\left(2-x\right)\left(x^2+4\right)>0\Leftrightarrow2-x>0\Leftrightarrow x< 2\\ b,\Leftrightarrow x+3>0\Leftrightarrow x>-3\\ c,\Leftrightarrow\left[{}\begin{matrix}x< -3\\x>4\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,2x-1=3
2x = 3+1
2x =4
x = 4:2
x=2
b,(x-4)-x+4=0
x-4-x+4=0
(x-x)+(-4+4)=0
0+0=0
x thuộc Z
c,tương tự
x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
BS: \(x\in \mathbb{Z}\)
\(a,\Rightarrow x\in\left\{1;2;3;4\right\}\\ b,\Rightarrow x\in\left\{-3;-2;-1\right\}\\ d,\Rightarrow x\in\left\{-1;-2;-3;...\right\}\\ e,\Rightarrow x\in\left\{-4;-5;-6;...\right\}\)
a.\(x\in\left\{1;2;3;4\right\}\)
b.\(x\in\left\{-3;-2;-1\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) ( x + 5 )( x - 4 ) = 0
\(\Rightarrow\)x + 5 = 0 hoặc x - 4 = 0
\(\Rightarrow\)x = - 5 hoặc x = 4
Vậy : x = - 5 hoặc x = 4 .
b ) ( 3 - x )(x - 3 ) = 0
\(\Rightarrow\)- ( x - 3 )( x - 3 ) = 0
\(\Rightarrow\)( x - 3 )2 = 0
\(\Rightarrow\)x - 3 = 0
\(\Rightarrow\)x = 3
Vậy : x = 3 .
a)\(\left(x+5\right)\left(x-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+5=0\\x-4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-5\\x=4\end{cases}}}\)
vậy x=-5 hoặc x=4
b)\(\left(3-x\right)\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3-x=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\x=3\end{cases}}}\)
vậy x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
x(x+2)=0
<=>x=0
hoac x+2=0
<=>x=0
hoac x=0-2
<=>x=0
x=-2 Vậy x=0 hoac x=-2
(x+3)(x-4)=0
<=>x+3=0
hoac x-4=0
<=>x=0-3
hoac x=0+4
<=>x=-3
hoac x=4 Vay x=-3 hoac x=4
\(\left(x-4\right).\left(3-x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=3\end{matrix}\right.\)
vậy...............
ai kết bạn với mình nào