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\(\left(2,8.x-32\right):\frac{2}{3}=90\)
\(2,8.x-32=90.\frac{2}{3}\)
\(2,8.x-32=60\)
\(2,8.x=60+32\)
\(2,8.x=92\)
\(x=92:2,8\)
\(x=\frac{230}{7}\)
\(\left(2,8:x-32\right):\frac{2}{3}=-90\)
\(2,8:x-32=\left(-90\right).\frac{2}{3}\)
\(2,8:x-32=-60\)
\(2,8:x=-28\)
\(x=\left(-28\right):2,8\)
\(x=-10\)
\(4-\left|x-2012\right|=\left(-2\right)^2\)
\(4-\left|x-2012\right|=-4\)
\(\left|x-2012\right|=8\)
\(\Rightarrow\orbr{\begin{cases}\left|x-2012\right|=8\\\left|x-2012\right|=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=2020\\x=2004\end{cases}}}\)
a ) (2,8x - 32 ) : 2/3 = -90
<=> 2,8x -32 = -60
<=> 2,8x = -28
<=> x = -10
b ) 4/5 + 5/7 :x =1/6
<=> 5/7:x = -19/30
<=> x = -150/133
a)\(\left(2,8x-32\right):\frac{2}{3}=-90\)
\(2,8x-32=-90\cdot\frac{2}{3}\)
\(2,8x-32=-60\)
\(2,8x=-60+32\)
\(2,8x=-28\)
\(x=-28:2,8\)
\(x=-10\)
Vậy x = -10
b) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{6}\)
\(\frac{5}{7}:x=\frac{1}{6}-\frac{4}{5}\)
\(\frac{5}{7}:x=\frac{-19}{30}\)
\(x=\frac{5}{7}:\frac{-19}{30}\)
\(x=\frac{-150}{133}\)
Vậy x = -150/133
=))
a)x+3/6=7/2
x =7/2-3/6
x =3
b)2,8+(3x-5/6)=2/2/5
14/5+(3x-5/6)=12/5
(3x-5/6)=12/5-14/5
3x+5/6=-2/5
3x =-2/5-5/6
3x =-37/30
x =-37/36:3
x =-37/90
A/\(\left(2,8x-32\right):\frac{2}{3}=-90\)
\(\left(\frac{28}{10}x-32\right)=\frac{-90}{1}.\frac{2}{3}\)
\(\left(\frac{14}{5}x-32\right)=\frac{-30}{1}.\frac{2}{1}\)
\(\left(\frac{14}{5}x-32\right)=-60\)
\(\frac{14}{5}x=-60+32\)
\(\frac{14}{5}x=-28\)
\(x=\frac{-28}{1}:\frac{14}{5}\)
\(x=\frac{-28}{1}.\frac{5}{14}\)
\(x=\frac{-2}{1}.\frac{5}{1}=-10\)
B/\(\left(4,5-2x\right).1\frac{4}{7}=\frac{11}{14}\)
\(\left(\frac{45}{10}-2x\right).\frac{11}{7}=\frac{11}{14}\)
\(\left(\frac{9}{2}-2x\right)=\frac{11}{14}:\frac{11}{7}\)
\(\left(\frac{9}{2}-2x\right)=\frac{11}{14}.\frac{7}{11}\)
\(\left(\frac{9}{2}-2x\right)=\frac{1}{2}.\frac{1}{1}=\frac{1}{2}\)
\(2x=\frac{9}{2}-\frac{1}{2}\)
\(2x=\frac{8}{2}\)
\(x=\frac{8}{2}:\frac{2}{1}=\frac{8}{2}.\frac{1}{2}\)
\(x=\frac{4}{2}.\frac{1}{1}=\frac{4}{2}=2\)
Tìm x, biết:
(2,8.x-32):2/3=90
=>(2,8.x-32) =90.2/3
=>2,8.x-32 =60
=>2,8.x =60+32
=>x =92:2,8
=>x =
Í mà đề sai rồi, xem lại giúp mk nha !
K viết lại đề là:
2,8 x X - 32 = 90 x \(\frac{2}{3}\)
2,8 x X - 32 = \(\frac{180}{3}=60\)
2,8 x X = 60 + 32
2,8 x X = 92
x = 92 : 2,8
x = gần 32 bn nhé, có thể viết thành phân số nếu bn muốn\(\frac{920}{28}=\frac{230}{7}\)
Hội con 🐄 chúc bạn học tốt!!!
a) -0,6 . x - 7/3 = 5,4 (sửa dấu phẩy thành dấu nhân)
=> \(-\frac{3}{5}x-\frac{7}{3}=\frac{27}{5}\)
=> \(-\frac{3}{5}x=\frac{27}{5}+\frac{7}{3}=\frac{116}{15}\)
=> \(x=\frac{116}{15}:\left(-\frac{3}{5}\right)=\frac{116}{15}\cdot\left(-\frac{5}{3}\right)=-\frac{116}{9}\)
b) 2,8 : \(\left(\frac{1}{5}-3x\right)=1\frac{2}{5}\)
=> \(\frac{1}{5}-3x=2,8:1\frac{2}{5}\)
=> \(\frac{1}{5}-3x=\frac{14}{5}:\frac{7}{5}=\frac{14}{5}\cdot\frac{5}{7}=2\)
=> 3x = \(\frac{1}{5}-2=-\frac{9}{5}\)
=> \(x=\left(-\frac{9}{5}\right):3=\left(-\frac{9}{5}\right)\cdot\frac{1}{3}=-\frac{3}{5}\)
Nên sửa lại đề câu a đi nhá :))
( 2,8x - 32 ) : 2/3 = -90
2,8x - 32 = -90.2/3
2,8x - 32 = -60
2.8x = -60+32
2.8x = -28
x = -10
(2,8.x-32):2/3=-90
=>2,8.x-32=90x2/3
=>2,8.x-32=60
=>2,8.x=60+32
=>2,8.x=92
=>x=92:2,8
=>x=230/7
( 2,8.x - 32 ) : \(\frac{2}{3}\) = - 90
= 2,8.x - 32 = 90. \(\frac{2}{3}\)
= 2,8.x - 32 = 60
= 2,8.x = 60 + 32
= 2,8.x = 92
x = 92 : 2,8
x = \(\frac{230}{7}\)
Vậy x bằng \(\frac{230}{7}\)